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3 years ago

A round silo is 55 feet tall and has a 24 foot radius. How high would a load of 38000 cubic feet of grain fill the silo?

Mathematics

1 answer:

VARVARA [1.3K]3 years ago

6 0

Find the volume of the silo.

The formula is: Volume = PI x r^2 x h

Replace volume with the volume of grain and solve for h:

38000 = 3.14 x 24^2 x h

38000 = 3.14 x 576 x h

38000 = 1808.64 x h

Divide both sides by 1808.64

h = 38000 / 1808.64

h = 21.01

The grain would be 21.01 feet ( round to 21 feet.)

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3 years ago

Caden buys 3.9 pounds of grapes that cost $1.80 per pound. Which expression can be used to find the total cost of the grapes ?

Ilya [14]

Answer:

1.80 times 3.9

Step-by-step explanation:

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3 years ago

Nitrates are groundwater contaminants derived from fertilizer, septic tank seepage and other sewage. Nitrate poisoning is partic

o-na [289]

Answer:

a) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.96})^2}=2401$

And rounded up we have that n=2401

b) $n=\frac{0.07(1-0.07)}{(\frac{0.02}{1.96})^2}=625.22$

And rounded up we have that n=626

And we see that if we have previous info about p the sample size varies a lot.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

Part a

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.02$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Since we don't have prior information about the population proportion we can use ase estimator $\hat p =0.5$ . And replacing into equation (b) the values from part a we got: