Answer:
y=x^3
Step-by-step explanation:
I don't know y sha
Step by step solution :<span>Step 1 :</span><span>Equation at the end of step 1 :</span><span><span> (((3•(x2))•(y4))3)
4•——————————————————
((2x3•(y5))4)
</span><span> Step 2 :</span></span><span>Equation at the end of step 2 :</span><span><span> ((3x2 • (y4))3)
4 • ———————————————
24x12y20
</span><span> Step 3 :</span><span> 33x6y12
Simplify ————————
24x12y20
</span></span>Dividing exponential expressions :
<span> 3.1 </span> <span> x6</span> divided by <span>x12 = x(6 - 12) = x(-6) = 1/<span>x6</span></span>
Dividing exponential expressions :
<span> 3.2 </span> <span> y12</span> divided by <span>y20 = y(12 - 20) = y(-8) = 1/<span>y8</span></span>
<span>Equation at the end of step 3 :</span><span> 27
4 • ——————
16x6y8
</span><span>Step 4 :</span>Final result :<span> 27
—————
4x6y<span>8</span></span>
Answer:
B
Step-by-step explanation:
Answer:
Step-by-step explanation:
Let points D, E and F have coordinates 
and 
1. Midpoint M of segment DF has coordinates
2. Midpoint N of segment EF has coordinates
3. By the triangle midline theorem, midline MN is parallel to the side DE of the triangle DEF, then points M and N are endpoints of the midsegment for DEF that is parallel to DE.
![\vec{BE}=[-2-(-6);\ 4-10]=[4;\ -6]](https://tex.z-dn.net/?f=%5Cvec%7BBE%7D%3D%5B-2-%28-6%29%3B%5C%204-10%5D%3D%5B4%3B%5C%20-6%5D)
![D(x;\ y)\\\\\vec{ED}=[x-(-2);\ y-4]=[x+2;\ y-4]\\\\\vec{ED}=\vec{BE}\ therefore\\\\ \ [x+2;\ y-4]=[4;\ -6]\to x+2=4\ and\ y-4=-6\\\\x=2\ and\ y=-2\\\\Answer:\ \boxed{A.\ (2;\ -2)}](https://tex.z-dn.net/?f=D%28x%3B%5C%20y%29%5C%5C%5C%5C%5Cvec%7BED%7D%3D%5Bx-%28-2%29%3B%5C%20y-4%5D%3D%5Bx%2B2%3B%5C%20y-4%5D%5C%5C%5C%5C%5Cvec%7BED%7D%3D%5Cvec%7BBE%7D%5C%20therefore%5C%5C%5C%5C%20%5C%20%5Bx%2B2%3B%5C%20y-4%5D%3D%5B4%3B%5C%20-6%5D%5Cto%20x%2B2%3D4%5C%20and%5C%20y-4%3D-6%5C%5C%5C%5Cx%3D2%5C%20and%5C%20y%3D-2%5C%5C%5C%5CAnswer%3A%5C%20%5Cboxed%7BA.%5C%20%282%3B%5C%20-2%29%7D)
