What is the lcd of 11/12 and 1/8

Calculate the rate of change.

Tpy6a [65]

Answer:

2

Step-by-step explanation:

Rise is 10 run is 5 Rate of Change is rise over run.

7 0

2 years ago

Can someone please help me find the answer to #19? I attached a photo of the problem

brilliants [131]

Answer:

21 packages

Step-by-step explanation:

4 ÷3/16= 4 x 16= 64/3=21 1/3 . 21 packages

hope this helps :)

4 0

2 years ago

A researcher records the hospital admission rates for coronary heart disease at 10 local hospitals. She finds that 2 different h

In-s [12.5K]

The central tendency researcher use to describe these data is "mode".

The value that appears most frequently in a data set is called the mode. One mode, several modes, or none at all may be present in a set of data. The mean, or average of a set, and the median, or middle value in a set, are two more common measurements of central tendency.

Calculation of mode is done by-

The number that appears the most frequently in a piece of data is its mode.
Put the numbers in ascending order by least to greatest, then count the occurrences of each number to quickly determine the mode.
The most frequent number is the mode.
Simply counting how many times each number appears in the data set can help you identify the mode, which is the number that appears the most frequently in the data set.
The figure with the largest total is the mode.
Example: Since it happens most frequently, the mode for the data set [5, 7, 8, 2, 1, 5, 6, 7, 5] is 5.

To know more about the mode of the data, here

brainly.com/question/27951780

#SPJ4

6 0

1 year ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

7 0

3 years ago

when two lines intersect one of the angel formed is 82 degrees what would be the measure if the angle vertical to the 82 degree

babymother [125]

Answer:

it would be 98 degrees

Step-by-step explanation:

if 2 lines inersect it means you create 4 angles. 2 of those angles are the same as well as the other ones so if one is 82 then the angle that counters it is 98

82+98=180

180 degrees equals line

7 0

3 years ago