Answer:
the 2nd one
Step-by-step explanation:
Answer:
T^75
Step-by-step explanation:
3 times 5 = 15
5 times 15 = 75
<h3>
Answer: 15x^(7/3) - 8x^(7/4) + x + 9000</h3>
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Explanation:
If you know the cost function C(x), to find the marginal cost, we apply the derivative.
Marginal cost = derivative of cost function
Marginal cost = C ' (x)
Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.


D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).
To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.
Therefore, we go from this

to this

which is the final answer.
Answer: 6
Step-by-step explanation: First rewrite 10 as 10/1 and 1 and 2/3 as 5/3.
Mixed numbers can be changed to improper fractions by multiplying the denominator by the whole number and then adding the numerator. We then put out numerator over our old denominator.
So we have 10/1 ÷ 5/3 or 10/1 × 3/5.
It's important to understand that dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the division to multiplication and flip the second fraction.
Now multiplying across the numerators and across the denominators, we have 30/5. Notice however that 30/5 is not in lowest terms so we divide the numerator and the denominator by the greatest common factor of 30 and 5 which is 6 and we end up with 6.
Therefore, 10 ÷ 1 and 2/3 = 6.