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neonofarm [45]
3 years ago
12

Qual é a area de um tirangulo escaleno cuja medidas são x,2x,3x?com calculo

Mathematics
1 answer:
zzz [600]3 years ago
6 0
E area de um triangulo escaleno e 3, de acordo com minhas notas.
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At Sara's new job she spent $11.52, $6.48, $5.99, $14.00, and $9.50 on lunch the first week. In the second week, she spent $4 mo
elena55 [62]
The total amount that Sara spent for her meals during the first week is,
                          $11.52 + $6.48 + $5.99 + $14.00 + $9.50 = $47.49
With an average of $9.498

During the second week, she spent $4 more making her total equal to $51.49. The average is equal to $10.298. The increase in the mean is equal to,
                         increase in mean  = $10.298 - $9.498 = $0.8<span>Comments</span>
4 0
3 years ago
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6 identical toys weigh 1.8 kg how much would 1 toy weigh using grams
kaheart [24]

Solution:

Given that, 6 identical toys weigh 1.8 kg

we know that, 1kilogram = 1000 grams

6 identical toys weigh in grams

1.8 * 1000 =1800

6 identical toys weigh 1800 grams

then calculating the weight of 1 toy by unitary method ,

weight of 1 toy =\frac{1800}{6} = 300 grams.

Hence, 1 toy would weigh 300 grams.



6 0
3 years ago
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I need help please on #7
vredina [299]
X=-4 is the answer for this question
7 0
3 years ago
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What is the answer for 144=-12(x+5) must show work
miskamm [114]

Answer:

<h2>x = -17</h2>

Step-by-step explanation:

-12(x+5)=144\qquad\text{divide both sides by (-12)}\\\\\dfrac{-12(x+5)}{-12}=\dfrac{144}{-12}\\\\x+5=-12\qquad\text{subtract 5 from both sides}\\\\x+5-5=-12-5\\\\x=-17

8 0
3 years ago
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The conditional relative frequency table below was generated by column using frequency table data comparing the number of calori
inessss [21]

Answer:

B. There is an association because the value 0.15 is not similar to the value 0.55

Step-by-step explanation:

Based on the above picture, for the nutritionist to determine whether there is an association between where food is prepared and the number of calories the food contains, there must be an association between two categorical variables.

The conditions that satisfy whether there exists an association between conditional relative frequencies are:

1. When there is a bigger difference in the conditional relative frequencies, the stronger the association between the variables.

2. When the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables.

For the given conditional relative frequency, we can see that there exists a significant difference between the columns of the table in the picture because 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45

We can conclude that there is an association because the value 0.15 is not similar to the value 0.55

3 0
3 years ago
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