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3 years ago

Write the expression in factored form: 16m4 power - n4 power

Mathematics

1 answer:

andre [41]3 years ago

4 0

16m^4 - n^4
= (4m^2 + n^2)(4m^2 - n^2)
= (4m^2 + n^2) (2m + n)(2m - n)

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Add and round to the correct number of significant digits: 13.8 + 60 70 73 73.8 74

LenaWriter [7]

When you add all the number together you get 364.6 round it = 365
Because 6 is > 5

4 0

3 years ago

Put these numbers in order from least to greatest.<br> -15-26/40, -15, 18/25, 15.85

Norma-Jean [14]

-15 26/40=<span>-15.65
-15
18/25=0.72
15.85
so From least to greatest
-15.65, -15, 0.72, and 15.85

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6 0

3 years ago

How is the Golden Ratio calculated from Fibonacci sequence? Please help me tyyy <3

AveGali [126]

Answer/Step-by-step explanation:

the fibonacci sequence is {1, 1, 2, 3, 5, 8, 13, 21, 34…} and in the visual for the Golden Ratio, if you look those are the those are the numbers that basically equals the golden ration, 1.618.

7 0

2 years ago

Helpppppp meeeeee 3/4x - 9 = 27 two step equations helppppppp

In-s [12.5K]

Isolate the x. Note the equal sign. What you do to one side, you do to the other.

First, add 9 to both sides

3/4x - 9 (+9) = 27 (+9)

3/4x = 36

Next, multiply 4/3 to both sides

(4/3)(3/4)x = 36(4/3)

x = 36(4/3)

Simplify.

x = 12(4)

x = 48

48 is your answer for x.

hope this helps

5 0

3 years ago

Read 2 more answers

After the mill in a small town closed down in 1970, the population of that town started decreasing according to the law of expon

wlad13 [49]

Answer:

$P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69$

And we can round this to the nearest up integer and we got 110194.

Step-by-step explanation:

The natural growth and decay model is given by:

$\frac{dP}{dt}=kP$ (1)

Where P represent the population and t the time in years since 1970.

If we integrate both sides from equation (1) we got:

$\int \frac{dP}{P} =\int kdt$

$ln|P| =kt +c$

And if we apply exponentials on both sides we got:

$P= e^{kt} e^k$

And we can assume $e^k = P_o$

And we have this model:

$P(t) = P_o e^{kt}$

And for this case we want to find $P_o$

By 1990 we have t=20 years since 1970 and we have this equation:

$143000 = P_o e^{20k}$

And we can solve for $P_o$ like this:

$P_o = \frac{143000}{e^{20k}}$ (1)

By 2019 we have 49 years since 1970 the equation is given by:

$98000 = P_o e^{49k}$ (2)

And replacing $P_o$ from equation (1) we got:

$98000=\frac{143000}{e^{20k}} e^{49k} =143000 e^{29k}$

We can divide both sides by 143000 we got:

$\frac{98000}{143000} =0.685 = e^{29k}$

And if we apply ln on both sides we got:

$ln(0.685) = 29k$

And then k =-0.01303024661[/tex]

And replacing into equation (1) we got:

$P_o = \frac{143000}{e^{-20*0.01303024661}}=110193.69$

And we can round this to the nearest up integer and we got 110194.

7 0

3 years ago