Answer:
0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
Step-by-step explanation:
We solve this question working with the probabilities as Venn sets.
I am going to say that:
Event A: Taking a math class.
Event B: Taking an English class.
77% of students are taking a math class
This means that 
74% of student are taking an English class
This means that 
70% of students are taking both
This means that 
Find the probability that a randomly selected student is taking a math class or an English class.
This is
, which is given by:

So

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.
Find the probability that a randomly selected student is taking neither a math class nor an English class.
This is

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class
37 is one of the factors . The orange divisors are the prime factors of the number 74. If you put them all together , you’ll have the factors 2•37=74
5x=x+4
5x-x=x-x+4
4x=4
4x/4=4/4
x=1
Hope this helps you. :)
Answer:
44
Step-by-step explanation:
Sara had 66 marbles in total. After taking 22 away, she is left with 44.
Hope this helps!