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3 years ago

1. Solve the system of equations 3r – 4s = 0 and 2r + 5s = 23.

2 answers:

8 0

4s = 3r
s = 3/4*r 
plug this into the second eqution and solve for the other variable: 
2r +5(3/4)r = 23 
23/4*r = 23 
r = 4 
plug this r into the above equation we solved: 
s = 3/4*r 
s = 3/4*4 
s = 3 
system is: 
{r=4, s=3}

Fiesta28 [93]3 years ago

3 0

3r-4s=0

2r+5s=23
2r=23-5s
r=(23-5s)/2

then 3(23-5s)/2=4s
69-15s=8s
69=23s
s=3
and r=(23-15)/2=4
____________
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3 years ago

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Read 2 more answers