Let X be the score on an english test which is normally distributed with mean of 31.5 and standard deviation of 7.3
μ = 31.5 and σ =7.3
Here we have to find score that separates the top 59% from the bottom 41%
So basically we have to find here x value such that area above it is 59% and below it is 49%
This is same as finding z score such that probability below z score is 0.49 and above probability is 0.59
P(Z < z) = 0.49
Using excel function to find the z score for probability 0.49 we get
z = NORM.S.INV(0.49)
z = -0.025
It means for z score -0.025 area below it is 41% and above it is 59%
Now we will convert this z score into x value using given mean and standard deviation
x = (z* standard deviation) + mean
x = (-0.025 * 7.3) + 31.5
x = 31.6825 ~ 31.68
The score that separates the top 59% from the bottom 41% is 31.68
Pretty sure it’s D and F because if you set (x-4)=0, x is 4 and if you set (x+7)=0, x is -7
Answer:
Let C be the cost price of the article. Then:
C(1+30%)=marked price
So:
C(1+30%)=C(1.3)
=1.3C
If the article is then marked down 35%, then its’ price would be:
1.3C(1–35%)=1.3C(.65)
=0.845 or 84.5% of its’ cost
Then:
0.845–1=-0.155
or, a 15.5% loss on the item
Answer:
if i labeled the triangle correctly BC= sqrt 97, ZX=32sqrt 2
Step-by-step explanation:
join my stream and tell me how to label the triangle
(ChildOfHermes)
