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lilavasa [31]
2 years ago
14

ANSWER NOW PLEASE

Mathematics
1 answer:
abruzzese [7]2 years ago
5 0

Given,

Total number of votes casted = 42,000

The winner received 3/5 of the votes.

To find,

How many votes did the winner not receive.

Solution,

Votes received by the winner is :

\dfrac{3}{5}\times 42000\\\\=25200

Votes didn't received by the winner = Total votes - votes received

= 42,000 -25200

= 16800

Hence, 16800  votes is not received by the winner.

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Solve for v: -10=-5/4v
vagabundo [1.1K]

Answer:

v = 8

Step-by-step explanation:

-10= -5/4v first multiply both sides of the equation by -4/5

-10(-4/5) = v this cancels out the right side.

multiply the left side.

so you are left with 40/5 = v

next, simplify you will get 8=v

8 0
2 years ago
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The length of a​ standard-sized rectangular rug is 2 feet longer than the width. Let x be the width. Which of the following quad
ipn [44]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
NO LINKS! Help me with this problem​
Basile [38]

{\qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

Equation of directrix is : y = 1, so we can say that it's a parabola of form : -

\qquad \sf  \dashrightarrow \: (x - h) {}^{2}  = 4a(y - k)

  • h = x - coordinate of focus = -4

  • k = y - coordinate of focus = 5

  • a = half the perpendicular distance between directrix and focus = 1/2(5 - 1) = 1/2(4) = 2

and since the focus is above the directrix, it's a parabola with upward opening.

\qquad \sf  \dashrightarrow \: (x - ( - 4)) {}^{2}  = 4(2)(y - 5)

\qquad \sf  \dashrightarrow \: (x  + 4) {}^{2}  = 8(y - 5)

\qquad \sf  \dashrightarrow \:  {x}^{2}  + 8x + 16 = 8y - 40

\qquad \sf  \dashrightarrow \: 8y =  {x}^{2}  + 8x + 56

\qquad \sf  \dashrightarrow \: y =  \cfrac{1}{8} {x}^{2}   + x + 7

6 0
1 year ago
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If z = 38 and x = 110, then what is the value of y?
sladkih [1.3K]

Answer:

First I need the whole question and second I am guessing around 76 or 72.

Step-by-step explanation:

3 0
2 years ago
Suppose a, b denotes of the quadratic polynomial x² + 20x - 2022 & c, d are roots of x² - 20x + 2022 then the value of ac(a
Alja [10]
<h3><u>Correct Question :- </u></h3>

\sf\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0 \: and \:  \\  \sf \: c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0 \: then \:

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) =

(a) 0

(b) 8000

(c) 8080

(d) 16000

\large\underline{\sf{Solution-}}

Given that

\red{\rm :\longmapsto\:a,b \: are \: the \: roots \: of \:  {x}^{2} + 20x - 2020 = 0}

We know

\boxed{\red{\sf Product\ of\ the\ zeroes=\frac{Constant}{coefficient\ of\ x^{2}}}}

\rm \implies\:ab = \dfrac{ - 2020}{1}  =  - 2020

And

\boxed{\red{\sf Sum\ of\ the\ zeroes=\frac{-coefficient\ of\ x}{coefficient\ of\ x^{2}}}}

\rm \implies\:a + b = -  \dfrac{20}{1}  =  - 20

Also, given that

\red{\rm :\longmapsto\:c,d \: are \: the \: roots \: of \:  {x}^{2}  -  20x  + 2020 = 0}

\rm \implies\:c + d = -  \dfrac{( - 20)}{1}  =  20

and

\rm \implies\:cd = \dfrac{2020}{1}  = 2020

Now, Consider

\sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d)

\sf \:  =  {ca}^{2} -  {ac}^{2} +  {da}^{2} -  {ad}^{2} +  {cb}^{2} -  {bc}^{2} +  {db}^{2} -  {bd}^{2}

\sf \:  =  {a}^{2}(c + d) +  {b}^{2}(c + d) -  {c}^{2}(a + b) -  {d}^{2}(a + b)

\sf \:  = (c + d)( {a}^{2} +  {b}^{2}) - (a + b)( {c}^{2} +  {d}^{2})

\sf \:  = 20( {a}^{2} +  {b}^{2}) + 20( {c}^{2} +  {d}^{2})

\sf \:  = 20\bigg[ {a}^{2} +  {b}^{2} + {c}^{2} +  {d}^{2}\bigg]

We know,

\boxed{\tt{  { \alpha }^{2}  +  { \beta }^{2}  =  {( \alpha   + \beta) }^{2}  - 2 \alpha  \beta  \: }}

So, using this, we get

\sf \:  = 20\bigg[ {(a + b)}^{2} - 2ab +  {(c + d)}^{2} - 2cd\bigg]

\sf \:  = 20\bigg[ {( - 20)}^{2} +  2(2020) +  {(20)}^{2} - 2(2020)\bigg]

\sf \:  = 20\bigg[ 400 + 400\bigg]

\sf \:  = 20\bigg[ 800\bigg]

\sf \:  = 16000

Hence,

\boxed{\tt{ \sf \: ac(a - c) + ad(a - d) + bc(b - c) + bd(b - d) = 16000}}

<em>So, option (d) is correct.</em>

4 0
2 years ago
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