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aleksandr82 [10.1K]
3 years ago
12

Why is musical notation important? What benefits do musicians and others receive from being able to write down and note aspects

of a musical piece?
Computers and Technology
1 answer:
madreJ [45]3 years ago
4 0
Most importantly, musicians can share their works with others.  Other people can see their musical ideas and can try and perform them too.   Nuances such as tempo, dynamics (loud soft, sweet, "harsh", are just some examples) can be understood even if the composer is not present and there is no recording to listen to.
Financial benefits can be realized from the sale of sheet music, scoring the piece, arranging the piece for bands, orchestras, etc. Conductors can lead an entire musical ensemble through the piece. 
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The spreadsheet below shows a list of fruits with their calorie count, grams of sugar, dietary fiber, and protein. Which set of
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Answer:

Filter Calories by over 100 calories, and sort Sugar in descending order.

Explanation:

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3 years ago
In this problem, we explore some of the properties of the CRC. For the generator G (=1001) given in Section 5.2.3, answer the fo
allochka39001 [22]

Answer:

b

Explanation:

5 0
3 years ago
Create a program in c/c++ which accepts user input of a decimal number in the range of 1 -100. Each binary bit of this number wi
kirill115 [55]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

void switch_fun(int input)

{

//array to store binary of input number

   int bin[7];

   // convert the number into binary

   for(int i=0; input>0; i++)

       {

           bin[i]=input%2;

           input= input/2;

       }

   // print the switch number and their status

   cout<<"Switch number:\t 1\t 2\t 3\t 4\t 5\t 6\t 7 \n";

   cout<<"status:      ";

   for(int j=6;j>=0;j--)

   {

   // if bit is 1 print "ON" else print "OFF"

       if(bin[j]==1)

           cout<<"\t ON";

       else

           cout<<"\t OFF";

   }

}

int main()

{

   int n;

   cout<<"enter the number between 1-100 only:");

   // read a number in decimal

   cin>>n

   // validate the input

   while(n<1 ||n>100)

   {

     cout<<"wrong input!! Input must be in between 1-100:"<<endl;

     cout<<"enter the number again :";

     cin>>n;

   }

// call the function with input parameter

  switch_fun(n);

return 0;

}

Explanation:

Read a decimal number from user. If the number is not between 1 to 100 the it will again ask user to enter the number until the input is in between 1-100.Then it will call the fun() with parameter n. First it will convert the decimal to binary array of size 7.Then print the status of switch.If bit is 1 then print "ON" else it will print "OFF".

Output:

enter the number between 1-100 only:-5

wrong input!! Input must be in between 1-100:

enter the number again :125

wrong input!! Input must be in between 1-100:

enter the number again :45

Switch number:   1       2       3       4       5       6       7

Status:          OFF     ON      OFF     ON      ON      OFF     ON

8 0
3 years ago
Good keyboarding technique includes ________
Svetlanka [38]

Answer:

Keeping you hands on the homerow keys

Explanation:

3 0
2 years ago
Read 2 more answers
If AL contains binary 1000 1111, which one will show the information of the binary bits in AL after performing operation SHR AL,
padilas [110]

Answer:

a) AL will contains 0011 1100

Explanation:

In assembly language, shifting bits in registers is a common and important practice. One of the shifting operations is the SHR AL, x where the x specifies that the bits be shifted to the right by x places.

SHR AL, 2 therefore means that the bits contained in the AL should be shifted to the right by two (2) places.

For example, if the AL contains binary 1000 1111, the SHR AL, 2 operation will cause the following to happen

Original bit =>                                        |   1  |  0 |  0  |  0  |  1 |  1 |  1 |  1 |

Shift once to the right =>                |  1 |   0 |  0  |  0  |  1 |  1 |  1 |  1 | (0) |

Shift once to the right =>          |  1 |  0 |  0  |  0  |  1 |  1 |  1 |  1 | (0) | (0) |

Notice;

(i) that there are two shifts - one at a time.

(ii) that the bits in bold face are the bits in the AL after the shift. Those that in regular face are those in the carry flag.

(iii) that the new bits added to the AL after a shift are the ones in bracket. They are always set to 0.

5 0
3 years ago
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