Answer:
v=9i+3j
Step-by-step explanation:
The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).
The vector v is found by subtraction the initial point from the terminal point.
v=<4,1>-<-5,-2>
v=<4--5,1--2>
v=<9,3>
We write v as multiples of the basis vectors to obtain:
v=9i+3j
Answer:
2.5
Step-by-step explanation:
Simplifying
2y + -1.7 = 3.3
Reorder the terms:
-1.7 + 2y = 3.3
Solving
-1.7 + 2y = 3.3
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Add '1.7' to each side of the equation.
-1.7 + 1.7 + 2y = 3.3 + 1.7
Combine like terms: -1.7 + 1.7 = 0.0
0.0 + 2y = 3.3 + 1.7
2y = 3.3 + 1.7
Combine like terms: 3.3 + 1.7 = 5
2y = 5
Divide each side by '2'.
y = 2.5
Simplifying
y = 2.5
We will turn the left side into the right side.
Use the identity:
Now use the identity
solved for sin^2 x and for cos^2 x.
You have to cancel out the variables and then you plug it into a calculator.
