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Vlada [557]
3 years ago
12

I need this done for tonight please help I’m stuck

Mathematics
2 answers:
lianna [129]3 years ago
7 0

Answer:

b

Step-by-step explanation:

dedylja [7]3 years ago
4 0

Answer:

B

Step-by-step explanation:

So when I was doing the math Equation 2 and Equation 3 were it so I hope that helped and I also hope I did my math right too XD

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I don’t get this Please help
ValentinkaMS [17]

Answer:

The second one! -5.99%

Step-by-step explanation:

3 0
3 years ago
Which of the following is the factored form of 9y2-121​
lukranit [14]
It's the first one.

If you work backwords, I'd say it's easier. 3y swuared is 9y2, and 11 squared is 121. Then just keep the sign the same
4 0
3 years ago
Ax - 6 = 7x - 26 {5}
Dmitry_Shevchenko [17]

Answer:A = 7 - 124/X


Step-by-step explanation:


6 0
3 years ago
Please Help Explain for brainliest
Anettt [7]
I would say Song 1 on the top could be NO, and Song 1 on the bottom could be ON, then Song 2 on the very top could be NO again, then on the bottom of the very top could OO, then on the bottom of that could be NN, and on he very bottom could be ON.
Hope this helps.
3 0
3 years ago
Prove that tan 10+tan 70'+taniou = tanio tanfo'tam 1oo.​
Galina-37 [17]

Question:

Prove that:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Answer:

Proved

Step-by-step explanation:

Given

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Required

Prove

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100)

Subtract tan(10) from both sides

- tan(10)+tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

tan(70) + tan(100) = tan(10). tan(70). tan(100) - tan(10)

Factorize the right hand size

tan(70) + tan(100) = -tan(10)(-tan(70). tan(100) + 1)

Rewrite as:

tan(70) + tan(100) = -tan(10)(1-tan(70). tan(100))

Divide both sides by 1-tan(70). tan(100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = \frac{-tan(10)(1-tan(70). tan(100))}{1-tan(70). tan(100))}

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10)

In trigonometry:

tan(A + B) = \frac{tan(A) + tan(B)}{1 - tan(A)tan(B)}

So:

\frac{tan(70) + tan(100)}{1 - tan(70)tan(100)} can be expressed as: tan(70 + 100)

\frac{tan(70) + tan(100)}{1-tan(70). tan(100)} = -tan(10) gives

tan(70 + 100) = -tan(10)

tan(170) = -tan(10)

In trigonometry:

tan(180 - \theta) = -tan(\theta)

So:

tan(180 - 10) = -tan(10)

Because RHS = LHS

Then:

tan(10) + tan(70) + tan(100) = tan(10). tan(70). tan(100) has been proven

6 0
3 years ago
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