Yes; to figure this out just plug the x,y values into the equation and make sure they come out true
Answer:
the initial population P₀ was 5938 people
Step-by-step explanation:
since the rate of increase of the population is proportional to the population itself, then the corresponding equation for a population P and time t is
dP/dt = k*P , where k= proportionality constant
dP/P = k*dt
∫dP/P =∫ k*dt
integrating between time t=0 (with P=P₀) and time t=t (with P=P)
ln (P/P₀)=k*t
if the population doubled , so P=2*P₀ at t=5 years then
ln (2*P₀/P₀)=k*5 years
k = ln 2 / 5 years
then the population is P=9000 for t= 3 years
ln (9000/P₀)=k*3 years
ln (9000/P₀)=ln 2 / 5 years *3 years
solving for P₀
P₀ = 9000 people * e^ (- ln 2 / 5 years *3 years ) = 9000 people *2 ^(-3 years / 5 years) = 5937.78 people ≈ 5938 people
therefore the initial population P₀ was 5938 people
The answer is N=11 since you do the parenthesis first then follow PEMDAS
Answer:
If only the fittest survive in certain enviorments other animals have to evolve to live in different places
Step-by-step explanation: