Answer:
a) P=0.8
b) P=0.67
c) P=0.05
d) P=0.33
e) P=0.45
Step-by-step explanation:
a. What is the probability that the household has only a cell phone and has high-speed Internet?
This probability is stated in the question: "Suppose of U.S. households having only a cell phone, 80% have high-speed Internet", so the probability is P=0.8.
b. What is the probability that the household has only a cell phone or has high-speed Internet?
This probability is equal to the sum of the probability of having only a cell phone and the probability of having high-speed internet, less the probability of having both (to avoid counting this household twice).
c. What is the probability that the household has only a cell phone and does not have high-speed Internet?
This is equal to the probability of not having high-speed internet given that it has a cell phone (complementaty of the proability of Point (a)) multiplied by the probability of having a cell phone.
d. What is the probability that the household does not have just a cell phone and does not have high-speed Internet?
This probability is complementary of the one calculated in Point (c).
e. What is the probability that the household does not have just a cell phone and does have high-speed Internet?
This is equal to the probability of having high-speed internet less the probability it has both (cell phone and internet).
To answer this specific question, <span>the all polar coordinates of point P are </span>(3, -π/4 + 2nπ) and [ -3, -π/4 <span>+ (2n + 1)π ]. </span>I am
hoping that this answer has satisfied your query about and it will be able to
help you, and if you’d like, feel free to ask another question.
Answer:
Step-by-step explanation:
Given that Jack did 3/5 of all problems on his weekend homework before Sunday. On Sunday he solved 1/3 of what was left and the last 4 problems. We have to find the number of problems assigned for weekend.
Let the total problems be x
∴ Problems assigned for weekend are
⇒ 
Answer:
d = 2
Step-by-step explanation:
Generate the first few terms
a₁ = (2 × 1) - 4 = 2 - 4 = -2
a₂ = (2 × 2) - 4 = 4 - 4 = 0
a₃ = (2 × 3) - 4 = 6 - 4 = 2
a₄ = (2 × 4) - 4 = 8 - 4 = 4
d = 0 - (- 2) = 2 - 0 = 4 - 2 = 2
To solve this, we work out the perimeter of the hexagon, by finding x, and we work out the perimeter of the pentagon by find y, and the compare them:
Perimeter of the Hexagon:
Since it is a regular hexagon, all the sides are the same: This means we can say that:
4x - 2 = x + 4 (Now lets solve this)
4x = x + 6 ( Add both sides by 2 to get 4x alone)
3x = 6 (Subtract both sides by x, to collect the x values)
x = 2 (Divide both sides by 3 to get what just x is)
Now we work out the length of one side by substituting the value for x in
x + 4 = 2 + 4
= 6
Now that we know the length of one side, we can multiply that by 6 to get the perimeter, because a hexagon has six sides.
6 * 6 = 36
Perimeter of the Pentagon
Since it is a regular Pentagon, all the sides are the same, just like the hexagon. This means we can say that:
5y - 8 = 2y + 1 (Now we solve this like we did before)
5y = 2y + 9 ( Add both sides by 8 to get 5y alone)
3y = 9 (Subtract both sides by 2y, to collect the y values)
y = 3 (Divide both sides by 3 to get what just y is)
Now we work out the length of one side by substituting the value for x in
2y + 1 = (2 * 3) + 1
= 7
Now that we know the length of one side, we can multiply that by 5 to get the perimeter, because a pentagon has 5 sides.
5 * 7 = 35
Since the perimeter of the hexagon is 36, and the perimeter of the pentagon is 35, we can see that:
The hexagon has the larger perimeter.
