3√10 + 7√15 - 6√10 - 4√15
3√10 - 6√10 + 7√15 - 4√15
-3√10 + 3√15
The answer is B.
Answer:
Step-by-step explanation:
<h3>to understand this</h3><h3>you need to know about:</h3>
<h3>given:</h3>
<h3>to find:</h3>
<h3>let's solve:</h3>
A-5B=2x+3-5(x²-5x+1)
- distribute -5 to the parentheses:2x+3-5x²+25x-5
- rewrite:-5x²+2x+25x-5+3
- combine like terms:-5x²+27x-2
and
we are done
Answer:
b = 44
Step-by-step explanation:
b + 90 + 46 = 180 (Supplementary Angles)
b = 180 - 90 - 46
b = 44
Answer:
heterozygous (Aa) are 0.085 = or 8.54%
Step-by-step explanation:
The heterozygous individuals are carriers of the sickle cell trait. They have a genotype of Aa and are represented by the 2pq term
in the H-W equilibrium equations.
According to the question 0.2% of the population is affected with sickle cell anemia, thus q^2
= 0.2% = 0.002 in decimal. So, q =
sqr(q^2)
or sqr(0.002) =
0.04472
and p + q = 1, thus p = 1 – q = 1 – 0.04472 = 0.96
Thus, A allele has a frequency of 0.96 and the a allele has a frequency of 0.04472. Therefore, the
percentage of the population that is heterozygous (Aa) and are carriers is = 2pq = 2× 0.04472× 0.96 =0.085 = or 8.54%
Answer:
<u>The constant is to add 1/10 to the previous term, therefore the unknown term is 5/10 or 1/2.</u>
<u>And this is the rule:</u>
<u>aₙ = aₙ₋₁ + 1/10 ⇒ a₁ = 3/10</u>
Step-by-step explanation:
Let's find the unknown term and the sequence:
1st term = 3/10
2nd term = 2/5 = 4/10
3rd term = x
4th term = 3/5 = 6/10
5th term = 7/10
<u>As we can see the constant is to add 1/10 to the previous term, therefore the unknown term is 5/10 or 1/2.</u>
<u>And this is the rule:</u>
<u>aₙ = aₙ₋₁ + 1/10 ⇒ a₁ = 3/10</u>
a₂ = a₁ + 1/10 ⇒ a₂ = 4/10 = 2/5 (Simplifying)
a₃ = a₂ + 1/10 ⇒ a₃ = 5/10 = 1/2 (Simplifying)
a₄ = a₃ + 1/10 ⇒ a₄ = 6/10 = 3/5 (Simplifying)
a₅ = a₄ + 1/10 ⇒ a₅ = 7/10
