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tino4ka555 [31]

2 years ago

11

What is the value of (-3)(5)(-4)

1 answer:

olasank [31]2 years ago

5 0

The answer is 60 bc -3 x -4 is 12, and 12x5 is 60

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All currently has $25. He is going to start saving $5 every week

sergij07 [2.7K]

Answer:

I believe the answer is b

Step-by-step explanation: I think the answer is b because he gets $5 every week and he already has $25 the only thing we dont know is the weeks and you multiply 5 by the weeks so, 5(how much he gets each week) times x (The amount of weeks) plus 25(the amount he already has) equals y(the amount of everything put together)

5 0

2 years ago

Solve for x: - 4 + x > 5

Rufina [12.5K]

Answer:

x>9 this is the correct answer

6 0

3 years ago

A- CE=CD <br> B- CE = CA <br> C- BF=DF <br> D- DF=EF<br><br> please help!!

Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that $\overleftrightarrow{FG}$ and $\overleftrightarrow{AB}$ are perpendicular.

The two statements if true that guarantee $\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ are;

$\overline{CE} = \overline{CD}$

$\overline{DF} = \overline{EF}$

Reasons:

The given diagram is the construction of the line $\mathbf{\overleftrightarrow{FG}}$ perpendicular to line $\mathbf{\overleftrightarrow{AB}}$ .

Required:

The two statements that guarantee that $\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ .

Solution:

From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line $\overleftrightarrow{AB}$ , therefore;

$\overline{CE} = \mathbf{\overline{CD}}$ arcs drawn from the same radius.

$\overleftrightarrow{FG}$ is perpendicular to line $\overleftrightarrow{AB}$ , given.

Therefore;

$\overline{DF} = \overline{EF}$ by perpendicular bisector theorem.

Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

7 0

2 years ago

21 less than a number, multiplied by 4, results in 108.Find the value of the unknown number.

Anni [7]

21 - 4x = 108

<em><u>Subtract 21 from both sides</u></em>

-4x = 87

<em><u>Divide both sides by -4</u></em>

x = -21.75

6 0

2 years ago

The smallest square number which can be divisible by 11 and 5

Elena L [17]

Answer:

3025

Step-by-step explanation:

let's look at it in this concept.

For a number to be divisible by 11 and 5. it must be a multiple of the LCM of 11 and 5.

LCM of 11 and 5=55

therefore the number is 55x, where x is a positive integer.

it is a said that the number is a perfect square

therefore the square root of 55x must be an integer.

$\sqrt{55x} = \sqrt{5 \times 11 \times x}$

the smallest value of x to make 55x a perfect square is....

$x = 11 \times 5 = 55$

Therefore the number is.... .

$55x = 55(55) = 3025$

<em>sweet</em><em> </em><em>right</em>

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6 0

2 years ago