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2 years ago

What is the value of (-3)(5)(-4)

Mathematics

1 answer:

olasank [31]2 years ago

5 0

The answer is 60 bc -3 x -4 is 12, and 12x5 is 60

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Fencing How much fencing is required to enclose a circular garden whose radius is 28 m? Use 3.14 for . About nothing m of fenci

Andru [333]

Answer:

175.84 m

Step-by-step explanation:

Given that:

A circular garden which has a radius of 28 m.

$\pi$ = 3.14

To find:

The fencing required to enclose the circular garden ?

Solution:

Here, we are given a circle and its radius.

We are required to find the perimeter of the circle in order to find the fencing required to enclose the circular garden..

Formula for finding the perimeter of a circle is:

Perimeter = $2\pi r$

where $r$ is the radius of the circle.

Using the given values in the formula:

Perimeter = $2\times 3.14 \times 28$ = <em>175.84 m</em>

Therefore, 175.84 m of fencing is required.

8 0

2 years ago

Sara bought 7 fish. Every month the number of fish she has doubles after m months she will have f fish, where f=7•2^m. How many

pav-90 [236]

After 2 months
f=7×2^2
f=28

3 0

2 years ago

Which expressions are equivalent to 5(1/3x+7)-3(1/2x-4)? Select three options. (There’s a picture)

Otrada [13]

3rd option

Step-by-step explanation:

solve and simplify to find

7 0

2 years ago

Can someone help me with system of equations?

nignag [31]

2x + y = 350
x + 2y = 475
3x + 3y = 825
x + y = 275
x = 275 - y
(plug back into first equation)
2(275 - y) + y = 350
550 - 2y + y = 350
550 - y = 350
-y =-200 or y = $200 (dog)
therefore, x = $75 (cats)
Check
2(75) + 200 = 350
75 + 400 = 475
HAPPINESS! :)

3 0

2 years ago

The sum of three consecutive terms in an arithmetic sequence is 27, and their product is 585. find the three terms.

sammy [17]

$\text{the three consecutive terms in an arithmetic sequence}\\a;\ a+d;\ a+2d\\\\\text{system of equals}\\\\ \left\{\begin{array}{ccc}a+a+d+a+2d=27\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}3a+3d=27&|:3\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}a+d=9&\to d=9-a\\a(a+d)(a+2d)=585\end{array}\right\\$
$\text{substitute to the second equation}\\\\a(a+9-a)(a+2(9-a))=585\\\\a(9)(a+18-2a)=585\\9a(18-a)=585\ \ \ |:9\\a(18-a)=65\\18a-a^2=65\ \ \ |\text{change the signs}\\a^2-18a=-65\\a^2-2a\cdot9=-65\ \ \ |+9^2\\\underbrace{a^2-2a\cdot9+9^2}_{(a-b)^2=a^2-2ab+b^2}=-65+9^2\\(a-9)^2=16\to a-9\pm\sqrt{16}\\a-9=-4\ \vee\ a-9=4\ \ \ |+9\\a=5\ \vee\ a=13\\\\d=9-5=4\ \vee\ d=9-13=-4$
$Answer:\ a=5;\ a+d=9; a+2d=13\ vee\ a=13;\ a+d=9;\ a+2d=5$

5 0

3 years ago