Answer:
See below in bold.
Step-by-step explanation:
1. The sequence is 1000, 2000, 4000, 8000.
2. The common ratio is 2000/1000 = 2.
3. Number of bacteria after 7 hours is 1000(2)^(7- 1)
= 64,000.
4. 1000(2)^(x-1) > 1,000,000
2^x-1 > 1000
x- 1 log 2 > log 10
x- 1 > 9.96
x > 10.96
During the 11th hour.
61 = 3b + 7
3b + 7 = 61
3b = 61 - 7
3b = 54
b = 54/3
b = 18.
Total tickets sold = 800
Total revenue = $3775
Ticket costs:
$3 per child,
$8 per adult,
$5 per senior citizen.
Of those who bought tickets, let
x = number of children
y = number of adults
z = senior citizens
Therefore
x + y + z = 800 (1)
3x + 8y + 5z = 3775 (2)
Twice as many children's tickets were sold as adults. Therefore
x = 2y (3)
Substitute (3) into (1) and (2).
2y + y + z = 800, or
3y + z = 800, or
z = 800 - 3y (4)
3(2y) + 8y + 5z = 3775, or
14y + 5z = 3775 (5)
Substtute (4) nto (5).
14y + 5(800 - 3y) = 3775
-y = -225
y = 225
From (4), obtain
z = 800 - 3y = 125
From (3), obtain
x = 2y = 450
Answer:
The number of tickets sold was:
450 children,
225 adults,
125 senior citizens.
-6 -8=-14C. When you subtract from a negative number the product will be smaller than when you started. Sometimes it helps to draw a number line and count that way.
