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Ludmilka [50]
3 years ago
11

Rob and Amy each improved their yards by planting rose bushes and shrubs. They bought their supplies from the same store. Rob sp

ent $100 on 8 rose bushes and 5 shrubs. Amy spent $112 on 8 rose bushes and 8 shrubs. What is the cost of one rose bush and the cost of one shrub? rose bush: $15,shrub: $5. rose bush: $10 , shrub: $4. rose bush: $7 , shrub: $5. rose bush: $13 , shrub: $2. PLS HELP WILL MARK BRAINLIEST
Mathematics
1 answer:
Lemur [1.5K]3 years ago
3 0

Answer:

The correct answer is that a rose bush costs $10 and a shrub costs $4

Step-by-step explanation:

To solve this, start by writing equations for what each spent. Use x for the cost of a rose bush and y for the cost of a shrub. Below would be the equations for each.

Rob: 8x + 5y = 100

Amy: 8x + 8y = 112

Now to find the cost, we multiply Rob's equation by -1 and add them together. This will get x to cancel and allow us to solve for y.

-8x - 5y = -100

8x + 8y = 112

------------------

3y = 12

y = 4

So we know the cost of a shrub is $4. Now we can plug that in to either of the original equations and solve for the rose bush cost.

8x + 5y = 100

8x + 5(4) = 100

8x + 20 = 100

8x = 80

x = 10

Which means that a rose bush costs $10.

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Bob rides his bike from his house to a friend's house. After riding 9 miles, he realizes he has traveled 3/4 of the way. How far
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Answer:

12 miles

Step-by-step explanation:

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8 0
3 years ago
A group of 5 people goes to the theater. If each ticket costs $6.50, is $50 a reasonable estimate for the cost of 5 tickets ? Ex
MAVERICK [17]
No it is not because its more then ten numbers away from the solution of the five tickets
6 0
3 years ago
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George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends
MariettaO [177]

For the circular cover we have:

A) The area is 379.94 ft²

B) The length of the rope must be 68.2 ft

<h3>How to get the area of the cover?</h3>

Remember that the area of a circle of radius R is given by the formula:

A = pi*R^2

Where pi = 3.14

In this case, the diameter of the pool is 20ft, then the radius is:

R = 20ft/2 = 10ft

And it must extend 12 inches beyond, then the radius of the cover must be:

R = 10ft + 12in

Now, we know that 1ft = 12 in, then we can rewrite the radius as:

R = 10ft +1ft = 11ft

Then the area of the cover is:

A = 3.14*(11ft)^2 = 379.94 ft^2

B) now we want to get the length of the rope, we know that the rope runs along the cover, then the length of the rope must be equal to the circumference of the cover.

Remember that the circumference of a circle of radius R is:

C = 2*pi*R

Then the length of the rope will be:

C = 2*3.14*11ft = 68.2ft

If you want to learn more about circles:

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7 0
2 years ago
What is (13-2x)(13-2x) ?
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(13-2x)(13-2x)

(13+-2x)(13+-2x)

(13)(13)+(13)(-2x)+(-2x)(13)+(-2x)(-2x)

169-26x-26x+4x^2

4x^2-52x+169


I hope that's help !

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3 0
3 years ago
Read 2 more answers
Flying to Kimpala with a tail wind a plane averaged 158km/hr. On the return trip the plane only average 112km/hr. While flying b
lora16 [44]

The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

<u>Step-by-step explanation:</u>

Let the speed of wind and speed of plane in still air  are  w  and  p km/h respectively.  

The effective speed on onward journey was  

p+w=158  ................(1)

The effective speed on return journey was  

p-w=112 ..............(2)

Adding equation (1) and equation (2) we get,  

⇒ (p+w)+(p-w) = 158+112

⇒ 2p = 270

⇒ p = 135

Putting value of p = 135 in p+w=158 we get:

⇒ p+w=158

⇒ 135+w=158

⇒ w=23

Therefore ,The speed of wind and speed of plane in still air  are  23  and  135 km/h respectively.

3 0
3 years ago
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