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const2013 [10]
3 years ago
6

Cheryl decorated a border of a birthday card with flowers. The flowers were 1/200 m apart. The length of the border was 1/5 m. T

here was a flower at each end of the border. How many flowers did she draw?
Mathematics
1 answer:
antiseptic1488 [7]3 years ago
6 0

Answer:

She draw 40 flowers

Step-by-step explanation:

Given

Length = \frac{1}{5}m

Flower = \frac{1}{200}m

Required

Determine the number of flowers

To do this, we simply divide the length of the border by the length of the flower.

Number = \frac{1}{5}/ \frac{1}{200}

Convert to multiplication

Number = \frac{1}{5}* \frac{200}{1}

Number =  \frac{200}{5}

Number = 40

<em>Hence, she draw 40 flowers</em>

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Mage has $36 to spend on movie tickets. Each movie ticket costs $4.50. How many tickets can he buy?
Stels [109]

Answer:

x = 8 tickets

Step-by-step explanation:

Given that,

Mage has $36 to spend on movie tickets.

Each movie ticket costs $4.50.

Let he bought x tickets. ATQ,

4.50x = 36

x=\dfrac{36}{4.5}\\\\=8

So, he can buy 8 tickets.

4 0
3 years ago
Is this right? i’ll give brainliest :)
jek_recluse [69]

It is.

x-10 \geq 0\\\\x \geq 10\\\\\\-5 +n< -6\\\\n < 5-6\\\\n< -1

6 0
3 years ago
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How many albums can Jada download if she downloads 30 individual songs?
Juli2301 [7.4K]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Simplify: cos2x-cos4 all over sin2x + sin 4x
GrogVix [38]

Answer:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

Step-by-step explanation:

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}

Apply formula:

\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right) and

\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)

We get:

=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}

=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}

=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}

=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}

=\frac{\sin\left(x\right)}{\cos\left(x\right)}

=\tan\left(x\right)

Hence final answer is

\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)

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a. (3+43)/2 = 23
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4 years ago
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