Answer:
Step-by-step explanation:
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Firstly we will make PMF
For X=0, P=(4/5)^3=64/125
For X=1, P=C(3,1)*(1/5)*(4/5)^2=3*16/125=48/125
For X=2, P=C(3,2)*(1/5)^2*(4/5)=3*4/125=12/125
For X=3, P=C(3,3)*(1/5)^3=1/125
So,
E[X^2]=1*48/125+2^2*(12/125)+3^2/125=0.84
E[X]=48/125+12/125*2+1/125*3=0.6
So,
E[X]^2=0.36