Answer:
Step-by-step explanation:
Note: If you have any queries related the answer please do comment. I would be very happy to resolve all your queries.
Firstly we will make PMF
For X=0, P=(4/5)^3=64/125
For X=1, P=C(3,1)*(1/5)*(4/5)^2=3*16/125=48/125
For X=2, P=C(3,2)*(1/5)^2*(4/5)=3*4/125=12/125
For X=3, P=C(3,3)*(1/5)^3=1/125
So,
E[X^2]=1*48/125+2^2*(12/125)+3^2/125=0.84
E[X]=48/125+12/125*2+1/125*3=0.6
E[X]^2=0.36
c 89+42x+42y
On day 1 :
First Machine= 89 stickers
Second Machine= none
On day 2 :
First Machine= ? stickers ( if in 1min = 42stickers
x min=?
( x min/1 min × 42stickers)
=42x stickers.
Second Machine=?stickers ( if in 1min = 42stickers
y min=?
( y min/1 min × 42stickers)
=42y stickers.
Total = 89 + 42x + 42y
minimum (-2,-2)
hope this will help
27 min i think
