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Hitman42 [59]
3 years ago
15

A youth ice hockey game has 3 periods that are each 20 minutes of Colin plays 12 minutes each. Which ratio shows Collins playing

time compared to the total number of minutes of possible playing time
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0
3 periods....20 minutes each.....3 * 20 = 60 total minutes playing time
colin plays 12 minutes each period...12 * 3 = 36 minutes 

Collins playing time to total playing time = 36/60 reduces to 9/15 or 9:15 or 9 to 15 <===
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I need help right away with the next problem.
Anna71 [15]

Answer:

  see below

Step-by-step explanation:

To convert the numbers to percentages, divide each number by the table total (80) and multiply by 100%. That is equivalent to multiplying each number by 1.25%. For example, 18·1.25% = 22.5% (middle table number).

5 0
3 years ago
Find an equation of the line through these points (15,2.2) (5,1.6). Write answer in a slope-intercept form
nadya68 [22]

Answer:

y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}

Step-by-step explanation:

Hi there!

Slope-intercept form: y=mx+b where m is the slope and b is the y-intercept (the value of y when x is 0)

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1} where two given points are (x_1,y_1) and (x_2,y_2)

Plug in the given points (15,2.2) and (5,1.6):

m=\frac{\displaystyle 1.6-2.2}{\displaystyle 5-15}\\\\m=\frac{\displaystyle -0.6}{\displaystyle -10}\\\\m=\frac{\displaystyle 0.6}{\displaystyle 10}\\\\m=\frac{\displaystyle 0.3}{\displaystyle 5}\\\\m=\frac{\displaystyle 3}{\displaystyle 50}

Therefore, the slope of the line is \frac{\displaystyle 3}{\displaystyle 50}. Plug this into y=mx+b:

y=\frac{\displaystyle 3}{\displaystyle 50}x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

y=\frac{\displaystyle 3}{\displaystyle 50}x+b

Plug in a given point and solve for b:

1.6=\frac{\displaystyle 3}{\displaystyle 50}(5)+b\\\\1.6=\frac{\displaystyle 3}{\displaystyle 10}+b\\\\1.6-\frac{\displaystyle 3}{\displaystyle 10}=\frac{\displaystyle 3}{\displaystyle 10}+b-\frac{\displaystyle 3}{\displaystyle 10}\\\\\frac{\displaystyle 13}{\displaystyle 10}=b

Therefore, the y-intercept is \frac{\displaystyle 13}{\displaystyle 10}. Plug this back into y=\frac{\displaystyle 3}{\displaystyle 50}x+b:

y=\frac{\displaystyle 3}{\displaystyle 50}x+\frac{\displaystyle 13}{\displaystyle 10}

I hope this helps!

5 0
3 years ago
A keycode must contain 2 letters and 3 numbers. The letters may be any letter of the alphabet. The numbers should be any number
OverLord2011 [107]
The English alphabet contains 26 letters (a, b, c, ...y, z). 

The digits from 0 to 9 are a total of 10.


A keycode contains 2 letters, and 3 numbers, for example:

AB 598;  MM 139;    NT 498; ...


So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of 

26*26=676 possible pairs of letters.


Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :

10*10*10=1,000 possible triples of numbers.


Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of 

676*1,000=676,000 keycodes.


Answer: 676,000
8 0
3 years ago
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LekaFEV [45]

Answer:

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