If f(x) = integral of 1/ (sqrt of t^3 +2)dt, then f'1 = ?
1 answer:
Differentiating an integral removes the integral. f(x) = integral of dt/sqrt(t^3 + 2) f'(x) = 1/sqrt(x^3 + 2) f'(1) = 1/sqrt(1^3 + 2) f'(1) = 1/sqrt(3) = sqrt(3)/3. I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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