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Bond [772]
3 years ago
15

One advantage of credit-card buying is the monthly list of expenditures you receive. True or False

Mathematics
2 answers:
Elenna [48]3 years ago
7 0
False

it is false because the funds will not last forever, you will run out of money

Rudik [331]3 years ago
6 0

Answer: False .

Step-by-step explanation:

False, it is not an advantage of credit-card buying to get the monthly list of expenditures.

As if we use credit card for every purchase, our liability would get increase, and to burden to pay off with interest will be increased as well.

So, it will be disadvantage instead of advantage to use credit card for every buying.

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Find the value of Z please help
JulijaS [17]
I think it is 1 because it is smaller than 1.5 so it would have to be 1
4 0
2 years ago
Purple Dog Pet Supply Inc. (PDPS) released its annual results and financial statements. Lucia is reading the summary in the busi
Rama09 [41]

Answer:

$35,000

Step-by-step explanation:

The computation of the dividend amount is given below:

As we know that

Dividend Paid = Net income - Retained earnings for current year

where,

Retained earnings for current year = This year - last year

= $500,000 - $425,000

= $75,000

Now

Dividend Paid is  

= $110,000 - $75,000

= $35,000

4 0
2 years ago
Car rentals involve a $130 flat fee and an additional cost of $31.67 a day. what is the maximum number of days you can rent a ca
Vladimir79 [104]
Represent the number of days by x. With this representation, the variable cost of the rental is 31.67x. The total cost is the sum of the fixed and variable costs. This value should not be more than $500. The equation below shows the relationship.
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Solving for x gives x ≤ 11.68
Thus, the maximum number of days to rent the car is only 11 days. 
6 0
2 years ago
Read 2 more answers
F(x) = 3 sin x<br> can you graph
kirill [66]

Answer:

Look at the photo

5 0
2 years ago
5. Find the general solution to y'''-y''+4y'-4y = 0
CaHeK987 [17]

For any equation,

a_ny^(n)+\dots+a_1y'+a_0y=0

assume solution of a form, e^{yt}

Which leads to,

(e^{yt})'''-(e^{yt})''+4(e^{yt})'-4e^{yt}=0

Simplify to,

e^{yt}(y^3-y^2+4y-4)=0

Then find solutions,

\underline{y_1=1}, \underline{y_2=2i}, \underline{y_3=-2i}

For non repeated real root y, we have a form of,

y_1=c_1e^t

Following up,

For two non repeated complex roots y_2\neq y_3 where,

y_2=a+bi

and,

y_3=a-bi

the general solution has a form of,

y=e^{at}(c_2\cos(bt)+c_3\sin(bt))

Or in this case,

y=e^0(c_2\cos(2t)+c_3\sin(2t))

Now we just refine and get,

\boxed{y=c_1e^t+c_2\cos(2t)+c_3\sin(2t)}

Hope this helps.

r3t40

5 0
3 years ago
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