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Dennis_Churaev [7]
3 years ago
6

The graph of the equation 2x-3y = 7 is a line. If a point on this line has an x-coordinate of 10, what

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

y = 13/3

Step-by-step explanation:

First input 10 as our x into the equation. So our new equation is 2(10) - 3y=7.

Once you simplify your equation would be 20 - 3y = 7. Subtract 20 from both sides. New equation is -3y = -13. Divide each side by -3. Your answer for y is 13/3.

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ivolga24 [154]
Just do 30 divided by 7 and put 7 as the denominator on top of the remainder
7 0
3 years ago
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Kevin drove for 4 hours and then stopped to eat dinner. The total distance he had driven at different time intervals is shown on
natta225 [31]

Answer:

If you want a simple average, you can add all the speeds you see and divide them by the number of how many they are.  

So firstly you have to calculate the speed of the first point, which is:  

20 miles/0.5 hour

That means: 40 miles/hour

That would be your first "speed"

Then you calculate all of them :speed1+speed2+speed3 = something.  

As an example: 20miles/hr + 40miles/hr+0miles/hr = 60miles/hr

Then, you divide it by how many "speeds" they are: 60miles/hr divided by 3 if I continue my previous example.

It is my first answer, and I hope I could help you a bit!

Sorry for the awkward English, as it is not my mother tongue.

Step-by-step explanation:

8 0
3 years ago
A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the he
Ulleksa [173]

Answer:

A. The football does not reach a height of 15ft

Step-by-step explanation:

Given

h(t) = -16t^2 + 30t

Required

Determine which of the options is true

The option illustrates the height reached by the ball.

To solve this, we make use of maximum of a function

For a function f(x)

Such that:

f(x) = ax^2 + bx + c:

f(\frac{-b}{2a}) = maximum/minimum

i.e we first solve for \frac{-b}{2a}

Then substitute \frac{-b}{2a} for x in f(x) = ax^2 + bx + c

In our case:

First we need to solve \frac{-b}{2a}

Then substitute \frac{-b}{2a} for t in h(t) = -16t^2 + 30t

By comparison:

b = 30

c = -16

\frac{-b}{2a} = \frac{-30}{2 * -16}

\frac{-b}{2a} = \frac{-30}{-32}

\frac{-b}{2a} = \frac{30}{32}

\frac{-b}{2a} = \frac{15}{16}

Substitute \frac{15}{16} for t in h(t) = -16t^2 + 30t

h(\frac{15}{16}) = -16(\frac{15}{16})^2 + 30(\frac{15}{16})

h(\frac{15}{16}) = -16(\frac{225}{256}) + \frac{450}{16}

h(\frac{15}{16}) = -(\frac{225}{16}) + \frac{450}{16}

h(\frac{15}{16}) = \frac{-225 + 450}{16}

h(\frac{15}{16}) = \frac{225}{16}

h(\frac{15}{16}) = 14.0625

This implies that the maximum height reached is 14.0625ft.

So, the option that answers the question is A because 14.0625 < 15

8 0
3 years ago
What is the value of y?<br><br> 3√3<br><br> 6√3<br><br> 9√3<br><br> 12√3
marshall27 [118]

6 \sqrt{3}
7 0
3 years ago
May someone please help me with this question
Cloud [144]

Answer:

2+i or 2-i (D)

Step-by-step explanation:

First you use the quadratic formula.  X= (-b +/- \sqrt{b^{2}-4ac })/2a

a=1

b=-4

c=5

X= (4 +/- \sqrt{16-20})/2

X=(4 +/- \sqrt{-4})/2

The square root of -4 is 2i.  i=√-1.  Therefore 2i= 2√-1 .If you simplify that, it becomes  √-4i.  

X= (4+/- 2i)/2

X= 2+/-i

X= 2+i or 2-i

7 0
3 years ago
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