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2 years ago

8

13,501 rounded to the nearest 10,000

2 answers:

fenix001 [56]2 years ago

7 0

You look at the number just to the right of the 10000s place, in this case 3, if it is less than five you round everything after the 10000s place down to zero, otherwise you round up the 10000s place and everything else to zero...

In this case 3 follows the 10000s place it becomes:

10000

galben [10]2 years ago

6 0

It would be 10,000 because if the number behind it is 4 or under it goes down if its 5 and up it goes up. even if you rounded 3501 to 4000 you would stilll get 10,000

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four families go to the cinema. the reid family take 2 adults and 2 children for £18 ; the mghee family take 1 senior, 2 adults

RoseWind [281]

Answer:

$\pounds 26.50$

Step-by-step explanation:

Let

x = cost for one adult

y = cost for one child

z = cost for one senior.

<u>The Reid family:</u>

take 2 adults and 2 children and paid $2x+2y$ that is $\pounds 18$ , so

$2x+2y=18$

<u>The Mghee family:</u>

take 1 senior, 2 adults and 1 child and paid $x+2x+y$ that is $\pounds 18.50$ , so

$x+2x+y=18.50$

<u>The Griffiths family:</u>

take 1 senior and 3 adults and paid $z+3x$ that is $\pounds 19.50$ , so

$z+3x=19.50$

You get the system of three equations:

$\left\{\begin{array}{l}2x+2y=18\\ \\z+2x+y=18.50\\ \\z+3x=19.50\end{array}\right.$

From the first equation:

$2y=18-2x\\ \\y=9-x$

From the third equation:

$z=19.50-3x$

Substitute them into the second equation:

$19.50-3x+2x+9-x=18.50\\ \\-3x+2x-x=18.50-19.50-9\\ \\-2x=-10\\ \\2x=10\\ \\x=5$

Then

$y=9-5=4\\ \\z=19.50-3\cdot 5=19.50-15=4.50$

Hence,

the cost for one adult is $\pounds 5$

the cost for one child is $\pounds 4$

the cost for one senior is $\pounds 4.50$

<u>The Linton family</u> takes 1 senior, 2 adults and 3 children and paid

$\pounds 4.50+2\cdot \pounds 5+3\cdot \pounds 4=\pounds 26.50$

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x + 4 1/3 = -2 5/6

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