Factor the denominator:
(3x-1)(x+2)
every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.
since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.
the answer here is C.
<span>given that P(x) --->p(x+6)+3
</span>
∴ x will become x+6
and P(x+6) will become P(x+6)+3
<span />
So, The graph of [p(x+6)+3] will be the same as the graph of [p(x)] but shifted 6 units to the left then shifted 3 units up
OR by another words, we need to make axis translations from (0,0) to (-6,3)
Shawndra is correct
She made two statements, and both are true:
1. It is not possible to draw a trapezoid that is a
rectangle.
This is true because a trapezoid<span> is a quadrilateral that has exactly one pair of
parallel sides, whereas a rectangle is a parallelogram (i.e. it has two
pairs of parallel sides)</span>
2. It is possible to draw a square that is a rectangle.
This is true because a rectangle refers to any parallelogram
with right angles. A square is also a parallelogram (has two pairs of opposite
sides) with right angles. In fact, all squares are rectangles; only that they
are a special kind of rectangle, where all the sides are equal in length.
Answer:
Less - He wouldn't be able to score as many points.
Hope this helps you out!
Answer:
Vota Trump
Step-by-step explanation:
