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Rus_ich [418]
3 years ago
5

All questions, please help me thanks

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0
73 teams
3min. 3sec.
18.5 miles

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c

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Solution:

Given:

H(x)=\frac{-6x^2}{(x-6)(x+1)}

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\begin{gathered} Equating\text{ the denominator to 0,} \\ (x-6)(x+1)=0 \\ x-6=0,x+1=0 \\ x=6,x=-1 \\  \\ Hence,\text{ undefined points exists at }x=6\text{ and }x=-1 \end{gathered}

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\begin{gathered} x

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\lbrace x|x

7 0
2 years ago
What is the value of b?<br><br> A. 100<br><br> B. 90<br><br> C. 80
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4 0
4 years ago
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Lucy I think you r welcome
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