Every number that has 0 as last digit and isn't decimal number, can be divided by 10 without remainder. It works for both positive or negative numbers. If last digit is different from 0, you will have remainder equal to that last digit. Even number 0 is divisible by 10 (the answer is 0 of course) because its last and only digit is 0.
If I understand your question well, I suppose you mean
(2y+3)(3y^2+4y+5)
so u just multiply all the things from different brackets.
2y*3y^2 = 6y^3
2y*4y = 8y^2
2y*2 = 4y
3*3y^2 = 9y^2
3*4y = 12y
3*5 = 15
so 6y^3+8y^2+4y+9y^2+12y+15
thats the answer BUT u need to collect the like terms, otherwise u probably wont get full marks on the question, so:
6y^3+17y^2+16y+15
i hope this helps :)
someone correct me if im wrong
Answer:
525 I think correct me if im wrong
Step-by-step explanation:
