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myrzilka [38]
3 years ago
5

Circle 1 has center (?4, ?7) and a radius of 12 cm. Circle 2 has center (3, 4) and a radius of 15 cm. What transformations can b

e applied to Circle 1 to prove that the circles are similar? Enter your answers in the boxes. Enter the scale factor as a fraction in simplest form. The circles are similar because the transformation rule (, ) can be applied to Circle 1 and then dilate it using a scale factor of 4 5?.
Mathematics
2 answers:
enot [183]3 years ago
6 0

Answer:

Hey! I just took the quiz and got 100%, the correct answer is: (x+7,y+11), and the last is 5/4. (: good luck.

shutvik [7]3 years ago
5 0

Answer: I think it’s 4

Step-by-step explanation:

Because by using a scale factor of 4 and 5 to simplify is 2

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The sum of two numbers is 31. The product of the two numbers is 150. What are the numbers?
mestny [16]
One way is to factor 150 and add the factors
150+1=151, nope
2+75=77, nope
3+50=53, nope
5+30=35, nope
6+25=31, yep

the numbers are 6 and 25
7 0
3 years ago
Read 2 more answers
Latita had 12 marbles. she gave 2 marbles to her friend she has 10/12 of her marbles left write answer in simplest form
zloy xaker [14]
The answer would be 5/6.
3 0
3 years ago
Solve for w.−(14w+8)+8=3
Stella [2.4K]
= -(14w + 8) + 8 = 3
= -14w - 8 + 8 = 3
= -14w = 3
w = -3/14

In short, Your Answer would be -3/14 

Hope this helps!
6 0
3 years ago
Read 2 more answers
find the coordinates of the point P on the parabola y=1-x^2 with domain 0≤x≤1 that minimize the area of the triangle enclosed by
coldgirl [10]

Let point P be with coordinates (x_0,y_0). Find the equation of the  tangent line.

1. If y=1-x^2, then y'=-2x.

2. The equation of the tangent line at point P is

y-y_0=-2x_0(x-x_0).

Find x-intercept and y-intercept of this line:

  • when x=0, then y=y_0+2x_0^2;
  • when y=0, then x=\dfrac{y_0}{2x_0}+x_0=\dfrac{y_0+2x_0^2}{2x_0}.

The area of the triangle enclosed by the tangent line at P, the x-axis, and y-axis is

A=\dfrac{1}{2}\cdot (2x_0^2+y_0)\cdot \left(\dfrac{y_0+2x_0^2}{2x_0}\right)=\dfrac{(y_0+2x_0^2)^2}{4x_0}.

Since point P is on the parabola, then y_0=1-x_0^2 and

A=\dfrac{(1-x_0^2+2x_0^2)^2}{4x_0}=\dfrac{(1+x_0^2)^2}{4x_0}.

Find the derivative A':

A'=\dfrac{2(1+x_0^2)\cdot 2x_0\cdot 4x_0-4(1+x_0^2)^2}{16x_0^2}=\dfrac{12x_0^4+8x_0^2-4}{16x_0^2}.

Equate this derivative to 0, then

12x_0^4+8x_0^2-4=0,\\ \\3x_0^4+2x_0^2-1=0,\\ \\D=2^2-4\cdot 3\cdot (-1)=16,\ \sqrt{D}=4,\\ \\x_0^2_{1,2}=\dfrac{-2\pm4}{6}=-1,\dfrac{1}{3},\\ \\x_0^2=\dfrac{1}{3}\Rightarrow x_0_{1,2}=\pm\dfrac{1}{\sqrt{3}}.

And

y_0=1-\left(\pm\dfrac{1}{\sqrt{3}}\right)^2=\dfrac{2}{3}.

Answer: two points: P_1\left(-\dfrac{1}{\sqrt{3}},\dfrac{2}{3}\right), P_2\left(\dfrac{1}{\sqrt{3}},\dfrac{2}{3}\right).

6 0
3 years ago
Recyclers pay five cents for every two aluminum cans recycled. how much are 100 cans worth?
Tpy6a [65]

Answer:

500

Step-by-step explanation:

Easy just times 5x100 or you could do 10, 20, ect 50 times in order to get 500. Sorry if this wasn't helpful lol.

5 0
2 years ago
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