All categories

3 years ago

Need reasons answer for this please!

Mathematics

1 answer:

Ugo [173]3 years ago

3 0

Step-by-step explanation:

1.Given .

2.Being vertically opposite angle.

3.Because sum of all interior angle of a triangle is always 180°.

4.From the statement of 3 number.

5.Because angle 4 = angle 3 and angle 6= angle 1 .

6.(suppose ,< is angle sign) solving this equation,

m<1 + m<2+ m<3 = m<3 + m<5 + m<1

You might be interested in

Solve 7k÷3=21 Math Problem

Daniel [21]

Do you mean 7000? Or k as a variable?

5 0

3 years ago

Read 2 more answers

F(x)=4x-3, g(x)=10-x<br> Work out gf(x)?

Sedbober [7]

Step-by-step explanation:

Given

f(x) = 4x - 3

g(x) = 10 - x

So Now

gf(x) = g( 4x - 3)

= 10 - 4x + 3

= 13 - 4x

Hope it will help :)❤

3 0

3 years ago

4) A jellybeans machine contains 25 green jellybeans, 57 red jellybeans, 31

stiv31 [10]

The answer is 12.5 because if you add them all together you get 200 and 25 of 200% is 12.5.

6 0

3 years ago

Find x<br> options;<br> a) 21√2/2<br> b) 21√2<br> c) 21√3/2<br> d) 7

pishuonlain [190]

The value of x is 21√2/2

The correct option is (A)

<h3>What is Trigonometry?</h3>

Trigonometry is a branch of mathematics that studies relationships between the sides and angles of triangles.

In triangle having angle 60.

sin 60 = P/ 7√3

√3/2= P/7√3

2P= 21

P= 21/2

Now again

cos 45= 21/2/x

1/√2 = 10.5/x

x= 21√2/2

Learn more about trigonometry here:

brainly.com/question/26719838

#SPJ1

6 0

2 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago