Solve for X and Y please

I need help with this question please ASAP before tomorrow!<br><br> Thank you :)

luda_lava [24]

23- right handed females

7 0

3 years ago

Read 2 more answers

A triangle has side lengths of

alexandr402 [8]

Answer:

P = ( 4y + 6 inches) + ( 8y - B ) inches + ( 5y + 3 ) inches

Step-by-step explanation:

Formula of Perimeter of triangle is = Sum of all sides.

P = A + B + C

6 0

3 years ago

Thx in advance for the help

lubasha [3.4K]

Answer: $x\geq 13$

Step-by-step explanation:

Given

The inequality is $2x-7\geq 19$

adding both side 7

$2x-7+7\geq 19+7\\2x\geq 26$

Multiply both sides by $\frac{1}{2}$

$\dfrac{1}{2}\times 2x\geq 26\times \dfrac{1}{2}\\\\x\geq 13$

the shaded region in the figure indicates the solution set.

6 0

3 years ago

A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d

Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

force = 4lb
direction = 4, -2
displacement = 7ft
direction = (0, 4) to (5,1)

The unit vector of the force is

$\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}$

$\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }$

The net force acting on the object is

$F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )$

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

$\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}$

$\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }$

The net displacement will be

$7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}$

The work done will be F.d

$w = f. d \\$

$w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs$

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

6 0

2 years ago

a recipe requires 2.5 teaspoons of sugar to make a candy bar. which equation shows the number of teaspoons of sugar, y, needed t

padilas [110]

If you would like to know the equation that shows the number of teaspoons of sugar needed to make x candy bars, you can calculate this using the following steps:

2.5 teaspoons of sugar ... 1 candy bar
y teaspoons of sugar = ? ... x candy bars = ?

2.5 * x = 1 * y
2.5 * x = y
y = 2.5 * x

The correct result would be <span>y = 2.5 * x.</span>

5 0

3 years ago