The approximate mass of the spherical weight is 51 pounds
To answer the question, we need to know what the mass of the sphere is
<h3>Mass of the sphere</h3>
The mass of the sphere m = ρV where
- ρ = density of steel = 0.284 lb/in³ and
- V = volume of sphere = 4πr³/3 where
- r = radius of sphere = 3.5 in
So, m = ρV
= ρ4πr³/3
Substituting the values of the variables into the equation, we have
m = ρ4πr³/3
= 0.284 lb/in³ × 4π(3.5 in)³/3
= 0.284 lb/in³ × 4π × 42.875 in³/3
= 48.706π lb/3
= 153.014 lb/3
= 51 lb
The approximate mass of the spherical weight is 51 pounds
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Answer:
I am just doing it for points
Step-by-step explanation:
The answer is blah blah blah
-2, -4/9 , 34%, 3/8. This is your answer
Part A: Chose some value for x, that means any amount of books to print for example 100 books, so x=100
Replace x=100 in C(x) and solve:
C(100)=3.5*100+1200=1550
Part B: Replace C(x) by 1900 and solve for x from the given equation:
1900=3.5x+1200
3.5x=1900-1200
x=700/3.5= 200
Part C: the statement C(20)=1270 means that 1270 is the cost for printing 20 books.
Part E: C(40.5)=1341.75 I think this statement is incorrect given the context because x means number of books to print so this value must be an integer number.
