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iogann1982 [59]
3 years ago
14

Which of the following would offer proof that a relation is a function?

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0
That would be the vertical line test
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I don't get it........
Helen [10]

Answer:

H. 32w = 496

Step-by-step explanation:

Since the length is 32 and you have the total area all you have to do is divide 496 by 32. And because w stands for width, you just solve for w.

I hope this helps :)

5 0
3 years ago
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Solve for xx. Express your answer as a proper or improper fraction in simplest terms.
kati45 [8]

Answer:

4/5

Step-by-step explanation:

hope this helps :)

4 0
3 years ago
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P(x) =x and q(x) = x-1Given:minimum x and Maximum x: -9.4 and 9.4minimum y and maximum y: -6.2 and 6.2Using the rational functio
Arte-miy333 [17]

we have the following function

\frac{p(x)}{g(x)}=\frac{x}{x\text{ -1}}

where x is between -9.4 and 9.4 and y is between -6.2 and 6.2.

We will first draw the function

from the graph, we can see that the zeroes are all values of x for which the graph crosses the x -axis

In this case, we see that that the only zero is at x=0.

Now, we have that the asymptotes are lines to which the graph of the function get really close to. On one side, we can see that as x goes to infinity or minus infinity, the values of the function get really close to 1. So the graph has a horizontal asymptote at y=1. Also, we can see that as x gets really close to 1, the graph gets really close to the vertical line x=1. So the graph has a vertical asymptote at x=1.

Recall that the domain of a function is the set of values of x for which the function is defined. From our graph, we can see that graph is not defined when x=1. So the domain of the function is the set of real numbers except x=1. Now, recall that the range of the function is the set of y values of the graph. From the picture we can see that the graph has a y coordinate for every value of y except for y=1. So, this means that the range of the function is the set of real numbers except y=1.

From the graph, we can see that we cannot draw the graph having a continous drawing. That is, imagine we take a pencil and start on one point on the graph on the left side. We can draw the whole graph on the left side, but we cannot draw the graph on the right side without lifting the pencil up. As we have to "lift the pencil up" this means that the graph is not continous

Finally note that as we have a vertical asymptote at x=1 and horizontal asymptote at y=1 we have that when y is 1 or x is 1, the function y=f(x)/g(x) is undefined

5 0
1 year ago
josh is looking to get a new car because he decided he was spending too much on gas. over the past year he found that he drove 7
Sveta_85 [38]

Josh's monthly fuel expenses are $1,050.

<h3><u>Prices</u></h3>

Given that Josh is looking to get a new car because he decided he was spending too much on gas, and over the past year he found that he drove 7,700 miles, and at current gas prices of $4.5 he was getting about 27 miles per gallon, To determine, if he bought a vehicle that realizes 33 miles per gallon, what might be a reasonable estimate of monthly gas costs, the following calculation must be made:

  • 27 = 100
  • 33 = X
  • 3300 / 27 = X
  • 122.22 = X
  • 122.22 = 100
  • 100 = X
  • 10000 / 122.22 = X
  • 81.81 = X
  • (7700 / 33) x 4.5 = X
  • 233.33 x 4.5 = X
  • 1050 = X

Therefore, Josh's monthly fuel expenses are $1,050.

Learn more about prices in brainly.com/question/18117910

#SPJ1

6 0
2 years ago
Which of the following options have the same value as
Keith_Richards [23]

Question:

Which of the following options have the same value as 65% of 20?

Choose 2 answers:

(A) 0.65⋅20

(B) 65/100 divided by 20

(C) 65/20 * 100

(D) 65 * 20

Answer:

Option A has the same value as  65% of 20

Step-by-step explanation:

Let x be the value of  65% of 20

x = 65\% of 20

x = \frac{65}{100} \times 20

x =0.65 \times 20

x =13

Thus 65% of 20 is 13

Now ,

<u>Solving Option A</u>

=> (0.65) \cdot (20)

=> 13

<u>Solving Option B</u>

=> 65/100 divided by 20

=>\frac{\frac{65}{100}}{20}

=>\frac{0.65}{20}

=>0.0325

<u>Solving Option C</u>

=>65/20 * 100

=>\frac{65}{20} \times 100

=>3.25 \times 100

=>325

<u>Solving Option D</u>

=> 65 * 20

=>65 \times 20

=> 1300

8 0
3 years ago
Read 2 more answers
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