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3 years ago

I need help!! 10 POINTS! NEED BY 8:30PM

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

7 0

Answer:

Area of Figure Shown (Diamond) = 200 square feet

Step-by-step explanation:

The diamond shape shown can be broken down into two triangles, one on top and one on bottom.

The area of a triangle is:

A = 0.5 * length * height

Lets find the area of the top triangle:

The base length is 20 and the height will be 20 - 15 = 5

So, Area would be:

Area = 0.5 * 20 * 5 = 50

Now, lets find area of bottom triangle (upside down triangle):

The base length is still 20

The height this time is 15 (given)

So, area would be:

Area = 0.5 * 20 * 15 = 150

Total Area (of Diamond) = 150 + 50 = 200 square feet

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3 years ago

(-7)-(-44)/22+((-4)*59) with calculation

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Hi,

$\frac{ ( - 7) - ( - 44)}{22 + (( - 4) \times 59)}$

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3 years ago

Read 2 more answers

How do you do this? plz I really need help.

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3 years ago

state domain and range, intercepts, relative max and relative mins points and values, intervals of increase and decrease, interv

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The domain of the graph is -∝ < x < ∝ and the range of the graph is -∝ < y < ∝. Also, the graph has no axis of symmetry

<h3>The domain and range of the graph</h3>

From the graph, we can see that the x values extend indefinitely

So, the domain of the graph is -∝ < x < ∝

From the graph, we can see that the y values extend indefinitely

So, the range of the graph is -∝ < y < ∝

<h3>The intercepts</h3>

This is where the graph crosses the axes

So, we have the intercepts to be

x-intercept = -4, -2 and 2
y-intercept = -9

<h3>Relative max and relative mins points and values, </h3>

The graph has a relative maximum at (3, 3) and the relative minimum are (0.5, 10)

<h3>Intervals of increase and decrease, </h3>

There are the intervals where the function increases and decreases

So, we have the intervals to be

Increasing interval: (0.5, ∝) and (-∝, -3)
Decreasing interval: (-3, 0.5)

<h3>Intervals of positive and negative,</h3>

There are the intervals where the function is positive and negative

So, we have the intervals to be

Positive interval: (-4, -2) and (2, ∝)
Negative interval: (-∝, -4) and (-2, 2)

<h3>The symmetry</h3>

This is the line that divides the graph equal part

In this case, the graph has no axis of symmetry

<h3>The end behavior</h3>

Using the intervals where the function is positive and negative, the end behavior is

As x ⇒ ∝, f(x) ⇒ +∝
As x ⇒ -∝, f(x) ⇒ -∝