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Answer:
B. x = 2√11
Step-by-step explanation:
The square of the length of the diagonal is ...
d² = 6² + 8² = 36 +64 = 100
Then the length of x is found from ...
d² +x² = 12²
x² = 144 -100 = 44 . . . . . subtract d²
x = √44 . . . . . . take the square root
x = 2√11
I can read it take a better picture
Answer:
C.g(x) = 5x²
Step-by-step explanation:
To find the equation for the function g(x), use the format for a quadratic equation. Without any up/down and left/right shifts, the form is y = ax².
Substituting "x" and "y" into the equation tells you if a point is on the graph.
"a" tells you the vertical stretch (greater than 1) or compression (greater than 0, less than 1).
In f(x) = x², a = 1 even though it's not written.
<u>Use the point (1, 5) on g(x) and substitute it</u> into the form for a quadratic function. Remember points are (x, y), so x = 1 and y = 5.
g(x) = ax²
y = ax² In function notation, g(x) replaces the "y". Switch it back to "y".
5 = a(1)² Substitute x = 1 and y = 5
5 = a(1) Solve the exponent first. (1)² = 1
5 = a When you multiply "a" by 1, the answer is just "a".
a = 5 Solved for "a". Put variable on left side for standard formatting.
With the quadratic form, substitute "a" into g(x).
y = ax²
g(x) = 5x²
The anwer is B, hope this was helpful
Answer:
Step-by-step explanation:
