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laila [671]
3 years ago
14

Please help asap 25 pts

Mathematics
2 answers:
Yuliya22 [10]3 years ago
7 0
1-(28-21)/28=.075

Answer is D
Irina-Kira [14]3 years ago
7 0
//////the answer is D/////////:
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Make q subject of the formula 2(q+p) = 1+5q
m_a_m_a [10]

Answer:

expand the equation

then make q the subject of the formal

6 0
2 years ago
How do you solve 2/5 (c+8.5) =18
Orlov [11]
Solve for c by simplifying both sides of the equation, then isolating the variable.



C=36.5
4 0
3 years ago
PLEASE HELP! I will award brainliest to the most helpful answer. I need an in depth explanation, not just the answer. How do you
Svetradugi [14.3K]

Answer:

y ≤ -4x+25

Step-by-step explanation:

First we need to figure out the equation for the line

The y intercept is  25

Next figure out the slope

slope = (y2-y1)/((x2-x1)

      = (49-25)/(-6-0)

      = 24/-6

    = -4

The equation for a line in slope intercept form is y = mx+b

y = -4x+25

This is a solid line so our inequality will have an equals in it.

It is shaded below, so y is less than.

If it was shaded above, y would be greater than

y ≤ -4x+25

8 0
3 years ago
What is the value of x in the equation 2x+7=1
iogann1982 [59]
2x + 7 = 1

Subtract 7 on both sides

2x = 1 - 7

2x = -6

Divide both sides by 2

x = -6/2

x = -3

Your answer is \boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\bf{x=-3}}}}}}}}}}}}}}}}}}}

8 0
3 years ago
Read 2 more answers
Please help :) this is exponential decay 10 pts
VMariaS [17]
$50.00 after 0 months and $37.50 after 6 months.
We first must calculate half-life using the attached formula.
Half-Life = (time * ln(2)) / ln (beginning amount/ending amount)
Half-Life = (6 * 0.69314718056) / ln (50.00 / 37.50)
Half-Life = ( <span> <span> <span> 4.1588830834 </span> </span> </span> ) / ln ( <span> <span> <span> 1.3333333333 </span> </span> </span> )
Half-Life = ( <span> <span> 4.1588830834 </span> </span> ) / 0.28768207245
Half-Life = <span> <span> <span> 14.456525038 </span> </span> </span> months

Now we need to calculate "lambda"
lambda = ln(2) / half-life
lambda = 0.69314718056 / <span>14.456525038
lambda = </span><span><span><span>0.0479470121 </span> </span> </span>

Next we have to use this formula:
Ending Amount = beginning amount • e^( -lambda • time )
(where "e" is the mathematical constant 2.718281828...)
Ending Amount = 50 * 2.718281828^<span>(-0.0479470121*24 months)
</span><span>Ending Amount = 50 * 2.718281828^(-1.1507282904)
</span>Ending Amount = 50 * <span> <span> <span> 0.3164062499 </span> </span> </span>
Ending Amount = <span> <span> <span> 15.82</span></span></span> dollars

**********************************************************************
As a DOUBLE-CHECK we can work this out every 6 months:

0 months $50
6 months = $50 - (50 *.25) = 37.50
12 months = $37.50 -(37.50 *.25) = <span>28.125
18 months = $28.125 -(28.125 * .25) = 21.09375 </span>
24 months = $21.09375 -(21.09375 * .25) = <span> <span> <span> 15.8203125 </span> </span> </span>

You'll find this page quite helpful:
http://www.1728.org/halflif2.htm


5 0
3 years ago
Read 2 more answers
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