I'm guessing that you want to find the segment area of a circle that has a radius AO = 8" and a chord AB with a length of 8".
Sine angle AOD = AE / OA
Sine angle AOD = 4 / 8
Sine angle AOD = .5
arc sine (.5) = 30 degrees
So, angle AOB = 60 degrees
Circle Area = PI * radius^2
Circle Area =
<span>
<span>
<span>
201.06</span></span></span>
Sector Area = (60/360) * 201.06
Sector Area = 33.51
Line OE^2 = AO^2 -AE^2
Line OE^2 = 64 -16
Line OE =
<span>
<span>
<span>
6.9282032303
</span>
</span>
</span>
Triangle AOB Area = OE*AE = <span>
<span>
<span>
6.9282032303 * 4
</span></span></span>Triangle AOB Area =
<span>
<span>
<span>
27.7128129211
</span>
</span>
</span>
Segment Area = Sector Area -Triangle AOB Area
Segment Area = 33.51 -<span>27.71
</span>Segment Area = 5.80
Answer:
y = 7/6x + 4/3
Step-by-step explanation:
find slope first
change in y over the change in x
-1-6/-2-4 = -7/-6 = 7/6
to be extra sure use this formula to find the y-intercept or b
y - 6 = 7/6 (x -4)
you can plug in either point
solve for y and you have the equation in slope intercept form or y=mx+b
I have no clue. I’m scared to get this type of math in the future.
Step-by-step explanation:
1/49 because 1 ticket got removed so the total of remaining tickets is 49
6x^2 - 2x + 1 is a quadratic formula from the form ax^2 + bx + c. This form of equation represents a parabola.
Finding 6x^2 - 2x + 1 = 0, means that you need to find the zeroes of the equation.
Δ = b^2 - 4ac
If Δ>0, the equation admits 2 zeroes and 6x^2 - 2x + 1 = 0 exists for 2 values of x.
If Δ<0, the equation doesn't admit any zero, and 6x^2 - 2x + 1 = 0 doesn't exist since the parabola doesn't intersect with the axe X'X
If Δ=0, the equation admits 1 zero, which means that the peak of the parabola is touching the axe X'X.
In 6x^2 - 2x + 1, a=6, b=-2, and c =1.
Δ= b^2 - 4ac
Δ=(-2)^2 - 4(6)(1)
Δ= 4 - 24
Δ= -20
Δ<0 so the parabola doesn't intersect with the Axe X'X, which means there's no solution for 6x^2 - 2x + 1 = 0.
I've added a picture of the parabola represented by this equation under the answer.
Hope this Helps! :)