3 years ago

Someone help me please!!

Mathematics

1 answer:

jolli1 [7]3 years ago

4 0

the answer will be C

8/5

1.6

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Find three consecutive odd integers so that the product of the second and third integer is 63

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<span>product of the second and third integer is 63
63=3*3*7
or
63=7*9 These are two consecutive integers.
We need three integers and the first one is missing so the solution:
5-7-9

</span>

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3 years ago

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Answer:

Given that

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Answer with Step-by-step explanation:

a. $x=b^p$

$y=b^q$

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$log x=plog b$

Using identity: $logx^y=ylogx$

$p=\frac{logx}{log b}=log_b x$

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$log y=qlog b$

$q=\frac{log y}{log b}=log_b y$

b. $xy=b^pb^q$

We know that

$x^a\cdot x^b=x^{a+b}$

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Substitute the values then we get

$log_b(xy)=(log_b x+log_b y)$

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3 years ago

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Answer:

Infinite

Step-by-step explanation:

I hope this helps, if it doesn't then just message me and ill be more than happy to help :)

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1 year ago

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Marrrta [24]

A. The student added before multiplying.
If they had multiplied 6 and 4 first, the next step would have been too divide. But since they added first, they got 36/24 or 3/2 when the answer should be 13.

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3 years ago