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3 years ago

PLEASE HELP IM BEGGING YOU!! FIND THE VALUE OF X

Mathematics

2 answers:

Akimi4 [234]3 years ago

7 0

X = 18.8 bc that’s the only thing that makes sense and us lazy people don’t need to work things out

AveGali [126]3 years ago

4 0

Answer:

Step-by-step explanation:

if 8+15 is about the length of the circle, the length is about 23

so 23 - 10 = 13 and the closest number to 13 is 12 so 12 is the answer

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Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

Using first principle, this gives:

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

Hence, the smallest sum is 2

3 0

3 years ago

Use the drop-down menus to complete the statements about factoring 14x2 + 6x – 7x – 3 by grouping.

Stella [2.4K]

Answer:1. GCF of the group ( 6 x - 3 ) is 3.

2. The common binomial factor is 2 x - 1.

3. The factored expression is: ( 2 x - 1 ) ( 7 x + 3 ).

Step-by-step explanation:

14 x² + 6 x - 7 x - 3 =

= ( 14 x² - 7 x ) + ( 6 x - 3 ) =

= 7 x ( 2 x - 1 ) + 3 ( 2 x - 1 ) =

= ( 2 x - 1 ) ( 7 x + 3 )

4 0

2 years ago

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Sergeeva-Olga [200]

The answer is sometimes

5 0

2 years ago

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((((((ASAP))))))On Tuesday afternoon at camp, Finn did archery and sailing before dinner. Archery started at 12:10 P.M. Finn spe

Andrei [34K]

Answer:

2:15

Step-by-step explanation:

legit just mush it up and add or sum .-.

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2 years ago

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There are 30 boys in a sporting club. 20 of them play hockey and 15 play volleyball. Each boys plays at least one of the two gam

SVETLANKA909090 [29]

Answer:

5 boys play all the two games

25 boys play only one game

Step-by-step explanation:

Sets

There are two sets defined in the question: one for the boys who play hockey (H) and the other for the boys who play volleyball (V).

All the boys play at least one of the two games, so no elements are outside both sets.

There are 30 boys in total. 20 of them play hockey and 15 play volleyball. Since the sum of both numbers is greater than the total of boys, the difference corresponds to the boys who play both games.

Thus 20 + 15 - 30 = 5 boys play both games

Given that 5 boys are shared by both sets, from the 20 playing hockey, 15 play ONLY hockey. From the 15 boys playing volleyball, 10 play ONLY volleyball.

Thus 15 + 10 = 25 boys play only one game.

The Venn diagram is shown in the image.

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2 years ago