So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
Answer:
C(x) = 7x + 10
Step-by-step explanation:
If the delivery charge is $10 for any number of board feet ordered.
If the delivery charge is $10 for each board feet ordered, the function would
be C(x) = (7 + 10)x = 17x
Answer:
Cluster Random Sample
Step-by-step explanation:
another example should help
Example—An airline company wants to survey its customers one day. So they randomly select 5 flights that day and survey every passenger on those flights, it's a cluster random Sample
it's kinda similar
hope it helps
If the width is w and the length is l, then 2w-2=l and 2w+2l=72 (using the perimeter equation). Plugging 2w-2 in for l, we get 2w+(2w-2)*2=72 and 6w-4=72. Adding 4 to both sides, we get 6w=76. After that, we divide both sides by 6 to get 74/6=w. Since l=2w-2=136/6, we get (136/6)(74/6)=656.75=area
