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3 years ago

6

14 times 4 times 18 times 6 times 5 Caleb draws $14 on each of 4 posters he draws 18 cats on each of six other posters if he dra

ws 5 more dogs on each poster with dogs how many dogs and cats does he draw

2 answers:

Rama09 [41]3 years ago

4 0

Just add it all up with a calculator

Rina8888 [55]3 years ago

4 0

I agree use a calculator bruh. Hope this helps. ( ͡° ͜ʖ ͡°)

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Which of the following scenarios is most likely to give the best approximation of the true probability of the event specified?

Sergeeva-Olga [200]

The most accurate and most likely probability is found by having a large, non-biased sample. The answer choice that shows this is D. Determine the ethnicity of 100 men (assumingly selected randomly) from a large city and determine the number who are Caucasian.

This answer choice showcases a large sample group, that was selected randomly from a large city. This would give you varied people to contribute to your study and give you an accurate representation of what the demographics of the city are.

I hope this helps! :)

8 0

4 years ago

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago

7/(3/2) = 2/g<br> What's the answer?

creativ13 [48]

Answer:

g = 3/7

Step-by-step explanation:

7/(3/2)

= 7 x (2/3)

= ( 2 x 7 )/3

= 14/3

14/3 = 2/g

Cross multiply,

14 x g = 3 x 2

g = ( 3 x 2 )/14

14 can be written as 2 x 7.

g = ( 3 x 2 )/( 2 x 7 )

2 in both numerator and denominator gets cancelled.

g = 3/7

8 0

2 years ago

Read 2 more answers

Which of these tables represents a function? HELP ASAP

vovangra [49]

Where’s your picture?

5 0

3 years ago

The length of a rectangle is 3 times the

sweet-ann [11.9K]

Answer:L= 3W

Perimeter = 2(l+w) = 40

2(3w+w) = 40

2*4w = 40

8w =40

w = 5

l = 3*5 = 15

Hope I helped

5 0

3 years ago