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Brums [2.3K]
3 years ago
11

Ummmm heyyy ahjkahskjdha;ishda

Mathematics
1 answer:
Lerok [7]3 years ago
3 0

Explanation: The <em>Y</em><em> </em><em> </em>values represent the oil. The <em>X</em><em> </em><em> </em>values represent the vinegar. The ratio of oil and vinegar is 3 to 2. If someone wanted to make half of the recipe, they would cut both of those amounts in half. Now the new ratio is 1.5 (the oil) and 1 (the vinegar).

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I met a man who said, if you can guess my age, I will pay you one dollar for each year that I have lived . I will also give you
Vladimir79 [104]
He could be 40321 years old.
If you divide 40321 by any odd or even number between 1 and 9, the remainder is 1.

I got this number by doing (2*3*4*5*6*7*8) + 1
4 0
3 years ago
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to go to the dog beach, it costs $3 plus $2 per dog. write an equation that shows this situation, where "x" represents the numbe
bixtya [17]
The equation representing this situation would be 3 + 2x = c, where c is the total cost.

To find the cost to bring 12 dogs, you will replace the x with the number 12.

3 + 2 x 12 = 27

The cost would be $27.
8 0
3 years ago
2log(2a - 1) = 0<br> How
Kryger [21]

Answer:

<h2>a = 1</h2>

Step-by-step explanation:

2\log(2a-1)=0\\\\\text{Domain:}\\\\2a-1>0\qquad\text{add 1 to both sides}\\2a-1+1>0+1\\2a>1\qquad\text{divide both sides by 2}\\\dfrac{2a}{2}>\dfrac{1}{2}\\\boxed{a>0.5}\\============================\\\\2\log(2a-1)=0\qquad\text{divide both sides by 2}\\\\\dfrac{2\!\!\!\!\diagup\log(2a-1)}{2\!\!\!\!\diagup}=\dfrac{0}{2}\\\\\log(2a-1)=0\qquad\text{use}\ \log_ab=c\iff b=a^c\\\\\log(2a-1)=\log10^0\\\\\log(2a-1)=\log1\iff2a-1=1\qquad\text{add 1 to both sides}\\\\2a-1+1=1+1\\\\2a=2\qquad\text{divide both sides by 2}\\\\\dfrac{2a}{2}=\dfrac{2}{2}\\\\a=1\in D

3 0
3 years ago
A jumper in the long-jump goes into the jump with a speed of 12 m/s at an angle of 20° above the horizontal. How far does the ju
weeeeeb [17]

Answer:

x = 9.5 m

Step-by-step explanation:

Given:

This problem is based on 2D motion kinematics equations:

V_0 = 12 m/s

\theta = 20^0

g=9.8 m/s^2

At maximum height:

V_y = 0

Components of initial velocity:

V_0x = V_0 cos (\theta) =(12 )(cos (20^0)) = 11.3 m/s

V_0x = V_0 sin (\theta) = (12)(sin (20^0)) = 4.10 m/s

To find time to reach maximum height:

V_y = V_0y -gt

Plugging in the known values:

0 = 4.10 - 9.8t

t = \frac{-4.10}{-9.8}

t = 0.418 s

Total time = 2t = 2(0.418) = 0.836 s

to find horizontal distance covered:

x = (V_0x)(t)\\x = (11.3)(0.836)\\x = 9.5 m

8 0
3 years ago
Can you plese help me
Luba_88 [7]

Answer:

I think Output relationship is 3,-2,3,-2 and Input relationship is -2,3,1,0.

7 0
2 years ago
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