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Brums [2.3K]
3 years ago
11

Ummmm heyyy ahjkahskjdha;ishda

Mathematics
1 answer:
Lerok [7]3 years ago
3 0

Explanation: The <em>Y</em><em> </em><em> </em>values represent the oil. The <em>X</em><em> </em><em> </em>values represent the vinegar. The ratio of oil and vinegar is 3 to 2. If someone wanted to make half of the recipe, they would cut both of those amounts in half. Now the new ratio is 1.5 (the oil) and 1 (the vinegar).

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Write any two numbers less than 15 , which has exactly four factors​
Xelga [282]

Answer:

4 can be divided by 1 and 2

6 can be divided by 1 and 2

12 is wrong because it can be divided by 1,2, and 4 so it has 6 factors instead of 4

Step-by-step explanation:

3 0
3 years ago
How do you find a common denominator?​
Dennis_Churaev [7]
You can just use the app SnapCalc it answers anything for free
4 0
3 years ago
I need help.. i really want to go sleep.. thank you so much...
Effectus [21]

Answer:

1) True 2) False

Step-by-step explanation:

1) Given  \sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i}

To verify that the above equality is true or false:

Now find \sum\limits_{k=0}^8\frac{1}{k+3}

Expanding the summation we get

\sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{0+3}+\frac{1}{1+3}+\frac{1}{2+3}+\frac{1}{3+3}+\frac{1}{4+3}+\frac{1}{5+3}+\frac{1}{6+3}+\frac{1}{7+3}+\frac{1}{8+3} \sum\limits_{k=0}^8\frac{1}{k+3}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

Now find \sum\limits_{i=3}^{11}\frac{1}{i}

Expanding the summation we get

\sum\limits_{i=3}^{11}\frac{1}{i}=\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}+\frac{1}{7}+\frac{1}{8}+\frac{1}{9}+\frac{1}{10}+\frac{1}{11}

 Comparing the two series  we get,

\sum\limits_{k=0}^8\frac{1}{k+3}=\sum\limits_{i=3}^{11}\frac{1}{i} so the given equality is true.

2) Given \sum\limits_{k=0}^4\frac{3k+3}{k+6}=\sum\limits_{i=1}^3\frac{3i}{i+5}

Verify the above equality is true or false

Now find \sum\limits_{k=0}^4\frac{3k+3}{k+6}

Expanding the summation we get

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3(0)+3}{0+6}+\frac{3(1)+3}{1+6}+\frac{3(2)+3}{2+6}+\frac{3(3)+4}{3+6}+\frac{3(4)+3}{4+6}

\sum\limits_{k=0}^4\frac{3k+3}{k+6}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}+\frac{12}{8}+\frac{15}{10}

now find \sum\limits_{i=1}^3\frac{3i}{i+5}

Expanding the summation we get

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3(0)}{0+5}+\frac{3(1)}{1+5}+\frac{3(2)}{2+5}+\frac{3(3)}{3+5}

\sum\limits_{i=1}^3\frac{3i}{i+5}=\frac{3}{6}+\frac{6}{7}+\frac{9}{8}

Comparing the series we get that the given equality is false.

ie, \sum\limits_{k=0}^4\frac{3k+3}{k+6}\neq\sum\limits_{i=1}^3\frac{3i}{i+5}

6 0
3 years ago
Number of Tickets, X 2 5 10 13 Cost, y $8.50 $21.25 $42.50 $55.25​
brilliants [131]

Answer:

4.25

Step-by-step explanation:

Take your cost and divide it by the number of tickets.

55.25/13 = 4.25

21.25/5 = 4.25

No matter which pair you use, the answer is 4.25

4 0
3 years ago
Area of a patio<br> 27’ wide by 36’ long
antoniya [11.8K]

Answer:

a=27×36

a=972 units²= or 972 square units

6 0
3 years ago
Read 2 more answers
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