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Svetllana [295]
3 years ago
9

How many different arrangements of the letters in the word SCHOOL are there?

Mathematics
2 answers:
enot [183]3 years ago
7 0
S. C. H. O. O. L.

S-six

C-Cruel

H-hours

O-of

O-our

L-Life’s
pogonyaev3 years ago
4 0
36; there are 6 letters in the word school so if you multiple it by 6 which is the amount of different places one letter could be, the result would be 36
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Use the dchnition of similarity to solve the following problem.
sveta [45]

Answer:

  1063 ft

Step-by-step explanation:

For shadow problems, we assume the sun's rays are parallel, so the triangles formed are similar. That means the ratio of height to shadow length is the same for each object.

  h/(580 ft) = (5.5 ft)/(3 ft)

  h = (5.5 ft)(580/3) ≈ 1063 ft

The height of the monument is about 1063 feet.

8 0
2 years ago
A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and
mr Goodwill [35]

Answer:

Bias for the estimator = -0.56

Mean Square Error for the estimator = 6.6311

Step-by-step explanation:

Given - A normally distributed random variable with mean 4.5 and standard deviation 7.6 is sampled to get two independent values, X1 and X2. The mean is estimated using the formula (3X1 + 4X2)/8.

To find - Determine the bias and the mean squared error for this estimator of the mean.

Proof -

Let us denote

X be a random variable such that X ~ N(mean = 4.5, SD = 7.6)

Now,

An estimate of mean, μ is suggested as

\mu = \frac{3X_{1} + 4X_{2}  }{8}

Now

Bias for the estimator = E(μ bar) - μ

                                    = E( \frac{3X_{1} + 4X_{2}  }{8}) - 4.5

                                    = \frac{3E(X_{1}) + 4E(X_{2})}{8} - 4.5

                                    = \frac{3(4.5) + 4(4.5)}{8} - 4.5

                                    = \frac{13.5 + 18}{8} - 4.5

                                    = \frac{31.5}{8} - 4.5

                                    = 3.9375 - 4.5

                                    = - 0.5625 ≈ -0.56

∴ we get

Bias for the estimator = -0.56

Now,

Mean Square Error for the estimator = E[(μ bar - μ)²]

                                                             = Var(μ bar) + [Bias(μ bar, μ)]²

                                                             = Var( \frac{3X_{1} + 4X_{2}  }{8}) + 0.3136

                                                             = \frac{1}{64} Var( {3X_{1} + 4X_{2}  }) + 0.3136

                                                             = \frac{1}{64} ( [{3Var(X_{1}) + 4Var(X_{2})]  }) + 0.3136

                                                             = \frac{1}{64} [{3(57.76) + 4(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [7(57.76)}]  } + 0.3136

                                                             = \frac{1}{64} [404.32]  } + 0.3136

                                                             = 6.3175 + 0.3136

                                                              = 6.6311

∴ we get

Mean Square Error for the estimator = 6.6311

6 0
3 years ago
A substance that is made of atoms of more than one type bound together is called a(n) ____________________ .
qaws [65]
<span>❅b. compound
Compound is a substance that is made of atoms of more then on type bound together. </span><span />
7 0
3 years ago
Solve for n:<br><br> 4n-40=7(-2n+2)
Sidana [21]

Step-by-step explanation:

hope this helped you :)) !!

8 0
2 years ago
Solve 8x2 + 6x + 5 = 0
MariettaO [177]
8 x 2 + 6x + 5=0
16 + 6x + 5=0
6x+21=0
6x+21-21=0-21
6x=-21
6x/6=-21/6
x=-7/2
5 0
3 years ago
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