Answer:
Input divided by 3 is output 28 and 38 are the outputs in the blank boxes
Step-by-step explanation:
33 divided by 3 is 11 126 divided by 3 is 42
P= 2L + 2W
40= 2(12) + 2W
40= 24 + 2W
16 = 2W
W= 8
If you get out a grid paper and mark them then just use BxHx.5 hope that this hleps
<u>Answer:</u>
CB // ED and both of BD and CE are transversals
The point E will be the image of point C by rotation 180° around point F
And The point D will be the image of point B by rotation 180° around point F
Rotation is a kind of transformation
So, ΔEDF will be the image of ΔCBF
So, ΔCBF ≅ ΔEDF
<u>Another way:</u>
So, ∠B = ∠D Alternate angles are congruent
and ∠C = ∠E Alternate angles are congruent
So, ΔCBF and ΔEDF have the following
1) ∠C = ∠E ⇒⇒⇒ Alternate angles are congruent (proved)
2) CB ≅ ED ⇒⇒⇒ Given
2) ∠B = ∠D ⇒⇒⇒ Alternate angles are congruent (proved)
From 1, 2 and 3
So, ΔCBF ≅ ΔEDF By SAS postulate
