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Perimeter of triangle ABC is 20 units.
Solution:
The image for reference is attached below.
Given AE = 2, BD = 5 and CF = 3
Two tangents drawn from an external point to a circle are equal in length.
AD = AE, BF = BD and CE = CF
Therefore, AD = 2, BF = 5 and CE = 3
Perimeter of the triangle = sum of the three sides
Perimeter of triangle ABC = AB + BC + CA
= AD + BD + BF + CF + CE + AE
= 2 + 5 + 5 + 3 + 3 + 2
= 20
Hence, perimeter of triangle ABC is 20 units.
