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spayn [35]
3 years ago
12

Jill is ordering a sandwich at a restaurant, and the server tells her that she can have up to five toppings: jalapeños, tomatoes

, spinach, mushrooms, and pickles. Since she cannot decide how many of the toppings she wants, she tells the server to surprise her. If the server randomly chooses which toppings to add, what is the probability that Jill gets just jalapeños and spinach?
Mathematics
1 answer:
kozerog [31]3 years ago
6 0

Jill can either only have 1 out of 5 toppings, 2 out of 5 toppings, until 5 out of 5 toppings. The total combinations would be:

total = 5C1 + 5C2 + 5C3 + 5C4 + 5C5

total = 31 combinations

 

So the probability that Jill will get just jalapenos and spinach (1 combination) is:

<span>Probability = 1/31 = 0.03225 = 3.23%</span>

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Answer and Explanation:

Given : Five males with an​ X-linked genetic disorder have one child each. The random variable x is the number of children among the five who inherit the​ X-linked genetic disorder.

To find :

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b) First we create the table as per requirements,

x      P(x)         xP(x)           x²            x²P(x)

0    0.029         0              0                0

1     0.147        0.147           1              0.147

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3    0.324       0.972         9              2.916

4    0.147        0.588        16              2.352

5    0.029       0.145         25            0.725

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The mean of the random variable is

\mu=\sum xP(x)=2.5

The standard deviation of the random sample is

Variance=\sigma^2

\sigma^2=\sum x^2P(x)-\mu^2

\sigma^2=7.436-(2.5)^2

\sigma^2=7.436-6.25

\sigma^2=1.186

\sigma=\sqrt{1.186}

\sigma=1.08

Therefore, The mean is 2.5 and the standard deviation is 1.08.

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