2 years ago

Can someone explain how to get the answer for the following question ?

Mathematics

1 answer:

zhenek [66]2 years ago

3 0

The answer to the question is 1-5

You might be interested in

How do I solve 4(5(6)) This is a hypothetical question

SSSSS [86.1K]

PEMDAS states that the value in the parenthesis should be evaluated first:
4(5*6)
4(30)
After just multiply the value in the parenthesis by the number outside of the parenthesis:
120

6 0

3 years ago

Read 2 more answers

F(x)=+6 Can you please brake this down for me step by step thank you

nikitadnepr [17]

Answer:

below in explanation

Step-by-step explanation:

This basically means that for any value of x, the answer will always be 6

6 0

2 years ago

Read 2 more answers

PLEASE HELP!!!

DIA [1.3K]

You would need 27 more dollars because f(x)=7x+2 plug in the 5 in x’s spot and you get 37 and so subtract it from 10 to get 27

7 0

2 years ago

Refer to the following data set: What is the median?

nadezda [96]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

In a certain Algebra 2 class of 25 students, 13 of them play basketball and 11 of them play baseball. There are 4 students who p

Flauer [41]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

Given: There are 2 classes of 25 students.

13 play basketball

11 play baseball.

4 play neither of sports.

Lets assume basketball as "a" and baseball as "b".

We know, probablity dependent formula; P(a∪b)= P(a)+P(b)-p(a∩b)

As given total number of student is 25

Now, subtituting the values in the formula.

⇒P(a∪b)= $\frac{13}{25} +\frac{11}{25} -\frac{4}{25}$

taking LCD as 25 to solve.

⇒P(a∪b)= $\frac{13\times 1+11\times 1-4\times 1}{25} = \frac{20}{25}$

∴ P(a∪b)= $\frac{4}{5}$

Hence, the probability that a student chosen randomly from the class plays both basketball and baseball is $\frac{4}{5}$ .

6 0

3 years ago