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astra-53 [7]
4 years ago
8

A box is contructed out of two different types of metal. the metal for the top and bottom, which are both square, costs $5 per s

quare foot and the metal for the sides costs $4 per square foot. find the dimensions that minimize cost if the box has a volume of 15 cubic feet.
Mathematics
1 answer:
patriot [66]4 years ago
3 0
Total cost, C = 8x^2 + 12xz 
volume, V = (x^2)*z = 10 
C = 8x^2 + 12x*10/x^2 
= 8x^2 + 120/x 
dC/dx = 16x - 120/x^2 = 0 
16x = 120/x^2 
x^3 = 120/16
 x = 1.957 ft

d^2C/dx^2 = 16 +240/x^3 = +ve for x = 1.957 
so, C is minimum when
x = 1.957 ft z = 2.61 ft

Length of the base x is 1.957 ft and height of side z is 2.61 ft
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Answer: 20 ft

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<em>Two triangles are similar when they have equal angles and proportional sides  </em>

It should be noted that to apply Thales' Theorem, it is necessary to establish <u>the two triangles are similar</u>, that is, that t<u>hey have the corresponding angles equal or that their sides are proportional to each other.  </u>

<u />

Now, if we measure the shadow of the flagpole and the shadow of the person, <u>at the same moment</u>, we can use the first Thales' Theorem to calculate the height of the flagpole, knowing the height of the person.

In this case we have two similar triangles (Figure attached) where H is the height of the flagpole, h=6 ft is the height of the person, A=5 ft is the length of the shadow of the flagpole and a=1\frac{1}{2}=1.5 ft is the length of the shadow of the person.

Having this clear, we can write the following relation with both similar triangles:

\frac{H}{h}=\frac{A}{a}   (1)

We know all these lengths except H, which is the value we want to to find.  

So, in order to approach this problem we have to find H from equation (1):  

H=\frac{A}{a}h  

H=\frac{5 ft}{1.5 ft}(6 ft)  

Then:

H=20 ft >>>>>This is the height of the flagpole

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