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3 years ago

A recycling center pays $0.10 per aluminum can and $0.05 per plastic bottle. The cheerleading squad wants to

Mathematics

1 answer:

diamong [38]3 years ago

3 0

Answer:

5000 aluminium cans

Step-by-step explanation:

So if the bring in ten aluminium bottles they make 1 dollar. If they bring in 50 they make 5 dollars.

If they 500 they make 50 dollars

If they bring in 5000 they make 500 dollars

Hope this helps!

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A stadium has 50,000 seats. Seats sell for $25 in section A, $20 in section B, and $15 in section C. The number of seats in sect

Novay_Z [31]

Answers:

section A = 25,000 seats

section B = 14,200 seats

section C = 10,800 seats

Your teacher may want you to leave out the commas from each number.

=============================================================

Work Shown:

A = number of seats in section A
B = number of seats in section B
C = number of seats in section C

A = B+C

A+B+C = 50,000

B+C+B+C = 50,000

2(B+C) = 50,000

B+C = 50,000/2

B+C = 25,000

C = 25,000 - B

25A + 20B + 15C = 1,071,000

25(B+C) + 20B + 15C = 1,071,000

25(25,000) + 20B + 15(25,000 - B) = 1,071,000

625,000 + 20B + 375,000 - 15B = 1,071,000

1,000,000 + 5B = 1,071,000

5B = 1,071,000 - 1,000,000

5B = 71,000

B = (71,000)/5

B = 14,200 is the number of seats in section B

C = 25,000 - B

C = 25,000 - 14,200

C = 10,800 is the number of seats in section C

A = B+C

A = 14,200 + 10,800

A = 25,000 is the number of seats in section A

--------------

Check:

A+B+C = 25,000+14,200+10,800 = 50,000

5 0

2 years ago

What is 10.4% as a fraction?

AlladinOne [14]

10.4% as a fraction is 104/1000

6 0

3 years ago

The population of Philadelphia in 1990 was 1,585,577. In 2010 the population was 1,526,006. What is the percent change the popul

UNO [17]

Answer:

-3.9% I.e there is decrease in the population

Step-by-step explanation:

Population @ 1990 = 1585577

Population @ 2010 = 1526006

% change =

(1526006-1585577)/1526006 × 100%

= -59571/1526006 ×100%

= -3.9%

7 0

2 years ago

Please help me....I really need help!!

scoundrel [369]

$\dfrac{c^2-4}{6c^4+15c^3}\div\dfrac{c^2+4c+4}{12c^3+30c^2}=\dfrac{c^2-2^2}{3c^3(2c+5)}\div\dfrac{c^2+2(c)(2)+2^2}{6c^2(2c+5)}\\\\_{\text{use}\ a^2-b^2=(a-b)(a+b)\ \text{and}\ (a+b)^2=a^2+2ab+b^2}\\\\=\dfrac{(c-2)(c+2)}{3c^3(2c+5)}\cdot\dfrac{6c^2(2c+5)}{(c+2)^2}=\dfrac{(c-2)}{c}\cdot\dfrac{2}{(c+2)}=\boxed{\dfrac{2(c-2)}{c(c+2)}}$

6 0

3 years ago

4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0

3 years ago