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dezoksy [38]
3 years ago
9

What is the function for the arithmetic sequence 2,7,12,17,22

Mathematics
2 answers:
vazorg [7]3 years ago
4 0
Hey there,

                                       Your question states: 
<span>
                       What is the function for the arithmetic sequence                                                                 
                                             (2,7,12,17,22)

By using the formula </span>[tex] a_{n} \ a_{1} + d(n-1) \ to \ get \ the \ sequence
<span>
The </span>mean of the <span>arithmetic sequence would be </span>\boxed{12}

And by identifying the sequence by using the formula, it would be . . .

\boxed{a_{n} =5n-3}

Hope this helps.
~Jurgen
Deffense [45]3 years ago
3 0


The common difference, d, is 5 and the starting value, a, is 2.
Filling this in the form of x_n=a+d(n-1)

<span>you get

</span>x_n = 2+5(n-1)
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5 0
2 years ago
How can i solve by completing the square 4r^2-28r=-49
Natalija [7]
To complete the square, the second degree term must have a coefficient of 1.
Since the second degree term here has a coefficient of 4, we start by dividing each term on both sides by 4.

4r^2 - 28r = -49

\dfrac{4r^2}{4} - \dfrac{28}{4}r = -\dfrac{49}{4}

r^2 - 7r = -\dfrac{49}{4}

Now we can complete the square.
First, we need to find what number completes the square.
We take the coefficient of the first degree term, -7 in this case.
Divide it by 2 and square it. -7 divided by 2 is the fraction -7/2.
Now we square -7/2 to get 49/4.
We add 49/4 to both sides.

r^2 - 7r + \dfrac{49}{4} = -\dfrac{49}{4} + \dfrac{49}{4}

(r - \dfrac{7}{2})^2 = 0

r - \dfrac{7}{2} = 0

r = \dfrac{7}{2}
3 0
3 years ago
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