Answer:
1. Pour the mixture through a filter to separate the sand; 2. Evaporate the liquid to separate the salt.
Step-by-step explanation:
Answer:
y = 2/3x - 5 or in standard form 3y = 2x - 5
Step-by-step explanation:
Remember this fact: Parallel lines have the same slope
Step 1 Solve for y so that the equation is in the slope- intersect form
2x - 3y = 6
-3y = -2x + 6
-3y/-3 = -2x/-3 + 6/-3
y = 2/3 x -2
now we know the slope is 2/3 or
when the equation is in Standard form Ax + By = C you can use this fact: slope = - A/B so the slope = -2/-3 = 2/3
Remember the Parallel lines have the same slope
Find the y-intersect "b" use the slope = 2/3 and point (6, -1)
y = mx + b
-1 = 2/3(6) + b
-1 = 4 + b
-5 = b
Now write the equation of line that is parallel to the given line and passes through point (6, -1)
y = 2/3x - 5 or in standard form 3y = 2x - 5
Answer:
- <em>0.75</em><em> liters of 5% hydrochloric acid solution </em>
- <em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>
Step-by-step explanation:
Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.
As Rajan need total of 1 liter of solution, so
i.e
--------------------1
As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

i.e
-------------2
Putting value of x from equation 1 in equation 2,





Putting the value of y in equation 1,

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters of 45% hydrochloric acid solution.